ÉRETTSÉGI VIZSGA ● 2015. május 13. Biológia angol nyelven emelt szint Javítási-értékelési útmutató 1411 BIOLÓGIA ANGOL NYELVEN EMELT SZINTŰ ÍRÁSBELI ÉRETTSÉGI VIZSGA JAVÍTÁSI-ÉRTÉKELÉSI ÚTMUTATÓ EMBERI ERŐFORRÁSOK MINISZTÉRIUMA Biológia angol nyelven — emelt szint Javítási-értékelési útmutató Instructions for marking the written paper 1. Always use red ink. 2. Put a tick next to each correct answer. Each correct tick is worth one point. Half a point is not to be given. If a question which is worth two points is answered correctly, put two ticks. 3. If there is a correct answer to a question which is not included in the marking scheme you can still accept it. The same principle applies to synonyms. (e. g.: platelets — trombocytes) 4. The equally acceptable, alternative answers are separated with a backslash (/) in the marking scheme. 5. At the end of each task add up the points in the grey boxes. 6. At the end of the examination paper fill in the summary table by giving the achieved score of each task and by adding them up calculate the total score. 7. Mark each correct answer with a tick on the margin in the optional essay. In the marking scheme only the most important terms and expressions are included in the correct logical order. You can also accept the answers if they are logically built up even if this logic is different from the one given in the marking scheme, unless it is otherwise stated in the given task. In the end, please add up the points of the correct answers and write them into the appropriate boxes of the summary chart. In the essay, points can only be given for answers responding to the guiding questions. 8. If the candidate started answering both optional tasks (A and B) act according to the instructions given under the heading of ‘Important Information’. 9. If the candidate is expected to formulate an answer in full sentences (e.g. reasonings and explanations) only grammatically correct sentences can be accepted. Do not subtract points for spelling mistakes but do not accept ambiguous sentences either. Good luck for your work! írásbeli vizsga 1411 2/7 2015. május 13. Biológia angol nyelven — emelt szint Javítási-értékelési útmutató I. Linne 13 points This task is based on the following chapters of the Detailed Requirements 1.1; 2.3.4; 3.4.1-2-4; 2.1.4 The source of figure: original / 100 koronás banknote 1. C 2. D 3. B 4. D 5. D 6. C 7. D 8. C 9. D 10. A 11. B 12. C 13. A Each correct answer is 1 point. II. Living forest and dead trees 12 points This task is based on the following chapters of the Detailed Requirements 3.3.1-2, 5.2.1 Source of Figure: original. Hőscincér: naturephoto-cz.comnagy-hoscincer-picture_hu-9637.html 1. symbiosis / mutualism 1 point 2. commensalism 1 point 3. A, D 1+1 = 2 points 4. A 1 point 5. B 1 point 6. B 1 point 7. B 1 point 8. B 1 point 9. D 1 point 10. C 1 point 11. E.g.:There is more light around the fallen trees than in other parts of the forest, the beech seedlings require a lot of light and that is why more of them can develop in these places. 1 point Reference to the uneven distribution of any environmental condition affecting the beech seedlings can be accepted. Other ideas like the increased humus content can also be accepted. The point can only be given if the reasoning is given in the required format. III. Laughter prescribed 5 points This task is based on the following chapters of the Detailed Requirements 4.6, 4.8.1-4. Pap János nyomán Ritmus magazin 2013, május 1. Sympathetic: blood circulation is speeded up / pulse rate increases / blood pressure (in men) increases. 1 point Parasympathetic: increased intestinal motility / digestive processes are activated / blood pressure decreases / pulse rate (in women) decreases. 1 point 2. Adrenal gland. 1 point 3. The alternating contraction and relaxation of the muscles exert a ‘muscle pump’ effect / during inspiration the chest cavity exerts a suction force on the veins ascending from the abdominal cavity. 1 point írásbeli vizsga 1411 3/7 2015. május 13. Biológia angol nyelven — emelt szint Javítási-értékelési útmutató 4. As a result of laughing there is an ‘increased number of natural killer cells and lymphocytes’ which are the cells responsible for carrying out various stages of the immune response. 1 point Alternative wording can also be accepted IV. Operons 9 points This task is based on the following chapters of the Detailed Requirements 4.8.4. and 6.1.3. The source of Figures: http://academic.pgcc.edu/~kroberts/Lecture/Chapter%207/regulation.html 1. structural genes 1 point repressor protein 1 point operator 1 point RNA polymerase / RNA synthesising enzyme 1 point lactose 1 point 2. A 1 point 3. The lactose switches on, the tryptophan inhibits the transcription of the structural genes. 1 point Alternative wording is also acceptable. 4. negative feedback 1 point 5. Tryptophan synthesis; reasoning: following the addition of the substance (tryptophan) the rate of enzyme synthesis is decreased. Reasoning is required for 1 point. 1 point V. Like people the salt 9 points This task is based on the following chapters of the Detailed Requirements 3.4.4., 4.4.4., 4.6., 4.7. and 4.8.4.The source of Figure: http://www.studyblue.com 1. 2. 3. 4. 5. B E C alimentary/digestive canal / skin 125 ml filtrate is released into the nephron per minute according to the graph, which means: 125×60×24 = 180 000 ml = 180 l 6. B 7. D 8. C 9. B Each correct answer is 1 point. VI. Graphs 11 points This task is based on the following chapters of the Detailed Requirements 1.3.; 4.5.1.; 4.6.3.; 4.8.1.; and 6.2.2. Figures: original 1. 2. 3. 4. 5. 6. A ,D, F, H B, J E I C, K G írásbeli vizsga 1411 1+1+1+1= 4 points 1+1= 2 points 1 point 1 point 1+1= 2 points 1 point 4/7 2015. május 13. Biológia angol nyelven — emelt szint Javítási-értékelési útmutató VII. Breakdown processes 11 points This task is based on the following chapters of the Detailed Requirements 2.1., 2.2.3. and 4.4. 1. C 2. A, E 3. urea, uric acid 4-10. 1 point 1 + 1 = 2 points 1 point Citric acid cycle Glycolisis 4. 7. 10. 9. 6. 8. 5. Terminal oxidation Each correctly placed number is 1 point, a total of 7 points. If a number is written in more than one place no point is to be given. VIII. Earlobes and genes 10 points This task is based on the following chapters of the Detailed Requirements 6.2.1 and 6.3.1 The source of Figure: Campbell and Reece: Biology. Pearson Inc., San Francisco, 2008 1. It is a recessive trait because the parents with unattached earlobes can have a child with attached earlobes. (Pl. A+B F vagy H+I L.) With reasoning 1 point 2. No, because if it was possible the man H could not have unattached earlobes. (The girl L received recessive alleles from both parents) With reasoning 1 point 3. No because if it was possible, there could be no girl with attached earlobes (however, K and L are girls). Only with reasoning. 1 point 4. E, M 1+1 = 2 points 5. 25% 1 point 6. The frequency of homozygous recessive individuals (those with attached earlobes): q2 = 0.04. The frequency of the recessive allele is its square root: q = 0.2. 1 point The frequency of individuals with unattached earlobes: p2 + 2pq = 0.96. The frequency of homozygous individuals with unattached earlobes: p2 = 0.64 The frequency of heterozygous individuals with unattached earlobes: 2pq = 0.32 1 point The proportion of heterozygotes within the population of people with unattached earlobes: 2pq / (p2 + 2pq) = 0.32: 0.96 = 0.333 1 point írásbeli vizsga 1411 5/7 2015. május 13. Biológia angol nyelven — emelt szint Javítási-értékelési útmutató Within the population of individuals with unattached earlobes a child with attached earlobes can only be born from the marriage of two heterozygotes. The possibility of such a marriage: 0.333 .0.333 = 0.111 Since the possibility of having a homozygous child from such a marriage is 0.25 the overall possibility in question: 0.111 . 0.25 = 0.028 (2.8%) 1 point Other correct solutions can also be accepted for a total of 4 points. IX. A Motor function of the nervous system 20 points This task is based on the following chapters of the Detailed Requirements 4.8.1.; 4.8.3. Two movements 7 points 1. D 2. D 3. B 4. A 5. A 6. C 7. D Each correct answer is 1 point. Essay 13 points • Withdrawal reflex / reflex of skin origin: protection 1 point receptors are the free / (naked) nerve endings detecting pain. 1 point Knee jerk reflex / reflex of muscle origin: maintaining balance / normal posture / muscle tone / adjusting muscle length 1 point receptors: muscle spindle / tendon organ (Golgi organ) 1 point • The function of the cerebellum is to coordinate the movement / maintain balance / fine tuning movements. 1 point • Frontal cerebral cortex – origin 1 point one part of it (pyramidal tract) passes down without synapsing on other neurons, while, 1 point other part of it (extrapyramidal tract) synapses on other neurons in the nuclei below the cortex and in the brainstem. 1 point While passing down, the tracts decussate, 1 point and terminate on the motor neurons in the ventral horn (of the spinal grey matter on the opposite side) / in the nuclei of the brain stem. 1 point Function: to learn new movements / to control fine movements (pyramidal tract) – naming a concrete learnt movement is also acceptable, and 1 point to control movements which (are/have become) automatic (e.g. walking) – naming a concrete learnt movement is also acceptable 1 point The consequence of injury: paralysis / impaired functioning of the opposite side. 1 point írásbeli vizsga 1411 6/7 2015. május 13. Biológia angol nyelven — emelt szint IX. B Javítási-értékelési útmutató Green circulation 20 points The pressure flow model 7 points This task is based on the following chapters of the Detailed Requirements 1.3, 3.4.3. and 5.1.1. 1. 2. 3. 4. 5. B, C 1+1 = 2 points B 1 point The stained liquid starts moving towards flask 2. 1 point A, E 1+1 = 2 points We can compare the speed at which the stained fluid is moving when the tap is open in the setup just described with the speed of fluid movement when the flasks are not immersed into the cylinders. 1 point Movement of water in plants – Essay 13 points • Plants can take up water from the soil if the water occurs in the soil water / in between the soil colloids, 1 point and the water is not available for the plants if it is strongly bound to the surface of the soil colloids (colloidal water, hydration shell). 1 point • Water is taken up through the extensions of epidermal cells / root hairs 1 point by osmosis / diffusion. 1 point In alkaline soil where the soil water has a high concentration of salt the concentration difference between the soil water and root cells is reduced and therefore osmosis / the uptake of water is hindered. • Water leaves the plant through the surface of green leaves and stems by evaporation / diffusion. 1 point 1 point 1 point 1 point 1 point • The regulation of water content is achieved by regulating the rate of evaporation / stomatal action. 1 point • Water molecules are used in photosynthesis, 1 point where the H atoms are used for the reduction of CO2 / are built into glucose/organic substances 1 point whereas the O atoms form O2 gas. 1 point írásbeli vizsga 1411 7/7 2015. május 13.
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