Area and Perimeter Area and Perimeter Curriculum Ready www.mathletics.com H SERIES Copyright © 2009 3P Learning. All rights reserved. First edition printed 2009 in Australia. A catalogue record for this book is available from 3P Learning Ltd. ISBN 978-1-921861-30-7 Ownership of content The materials in this resource, including without limitation all information, text, graphics, advertisements, names, logos and trade marks (Content) are protected by copyright, trade mark and other intellectual property laws unless expressly indicated otherwise. You must not modify, copy, reproduce, republish or distribute this Content in any way except as expressly provided for in these General Conditions or with our express prior written consent. Copyright Copyright in this resource is owned or licensed by us. 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This may lead to an increase in the fees for educational institutions to participate in the relevant scheme. Published 3P Learning Ltd For more copies of this book, contact us at: www.3plearning.com/contact/ Designed 3P Learning Ltd Although every precaution has been taken in the preparation of this book, the publisher and authors assume no responsibility for errors or omissions. Neither is any liability assumed for damages resulting from the use of this information contained herein. This booklet shows how to calculate the area and perimeter of common plane shapes. Football fields use rectangles, circles, quadrants and minor segments with specific areas and perimeters to mark out the playing field. Write down the name of another sport that uses a playing field or court and list all the plane shapes used to create them below (include a small sketch to help you out): Sport: Shapes list: Q Use all four squares below to make two shapes in which the number of sides is also equal to four. Compare the distance around the outside of your two shapes. Write down what you discovered and whether or not it was different from what you expected. Work through the book for a great way to do this Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 1 How does it work? Area and Perimeter Area using unit squares Area is the amount of flat space a shape has inside its edges or boundaries. A unit square is a square with each side exactly one unit of measurement long. 1 unit Little dashes on each side mean they are all the same length. Area (A) = 1 square unit = 1 unit2 (in shorter, units form) So the area of the shaded shape below is found by simply counting the number of unit squares that make it. 1 unit 1 2 3 4 Area (A) = 10 square units 5 6 7 8 = 10 unit2 9 10 Here are some examples including halves and quarters of unit squares: Calculate the area of these shapes (i) Area (A) = 2 whole square units + 2 half square units = 2 square units + 2 # 1 square units 2 = ^2 + 1h square units 1 unit = 3 units2 When single units of measurement are given, they are used instead of the word ‘units’. (ii) 1 cm 2 H 9 SERIES TOPIC Area (A) = 2 whole squares + 2 half squares + 2 quarter squares 1 square cm + 2 # 1 square cm = 2 square cm + 2 # 2 4 = ^2 + 1 + 0.5h square centimeters = 3.5 cm 2 Area and Perimeter Mathletics ©3P Learning Ltd How does it work? Your Turn Area and Perimeter Area using unit squares 1 Calculate the area of all these shaded shapes: a b 1 unit Area = whole squares 1 mm Area = units2 = whole squares mm2 = 1 unit c d 1 m Area = whole + m2 + = half squares # Area = whole + half squares = units2 + # 1 m2 2 m2 = units2 = e 1 units2 2 f 1 cm 1 unit Area = whole + quarter squares = units2 + # Area = 1 units2 4 cm2 + = units2 = whole + quarter squares # 1 cm2 4 cm2 = g 1 unit Area = whole + half + = units2 + # = 1 units2 + 2 # 1 units2 4 units2 Area and Perimeter Mathletics quarter squares ©3P Learning Ltd H 9 SERIES TOPIC 3 How does it work? Your Turn Area and Perimeter Area using unit squares 2 Calculate the area of these shaded shapes, using the correct short version for the units: a b 1 cm 1 unit Area = Area = c d 1 mm 1 m Area = Area = e f 1 mm 1 unit Area = Area = g h 1 km IN G US UN ING IT SQ US R E S * AR E A UA UNI T SQ ...../...../20.... R UA E S * AR E A 1 cm Area = 4 H 9 SERIES TOPIC Area = Area and Perimeter Mathletics ©3P Learning Ltd How does it work? Your Turn Area and Perimeter Area using unit squares 3 Shade shapes on these square grids to match the area written in square brackets. a 68 units2 @, using whole squares only. b 1 unit c 1 unit 63 mm2 @, include quarter squares in d your shape. 1 mm 4 65 units2 @, include half squares in your shape. 64.5 cm2 @, include halves and quarters. 1 cm An artist has eight, 1 m2, square-shaped panels which he can use to make a pattern. The rules for the design are: - the shape formed cannot have any gaps/holes. i.e. or 1 m - it must fit entirely inside the display panel shown, - all the eight panels must be used in each design. How many different designs can you come up with? Sketch the main shapes to help you remember your count. Number of different designs you found = Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 5 How does it work? Area and Perimeter Perimeter using unit squares The word perimeter is a combination of two Greek words peri (around) and meter (measure). Finding the perimeter (P) means measuring the distance around the outside! Start/end of path around the outside 1 unit Perimeter (P) = 1 unit + 1 unit + 1 unit + 1 unit = 4 # 1 unit Remember, little dashes on each side mean they are all the same length. = 4 units These examples shows that we only count all the outside edges. Calculate the perimeter of these shapes formed using unit shapes (i) Start/end of path around the outside 2 units 1 unit 1 unit 2 units Perimeter (P) = 1 + 2 + 1 + 2 units Sides of unit squares inside the shape not included = 6 units It does not matter where you start/finish, but it is usually easiest to start from one corner. (ii) 3 units 1 unit 1 unit 1 unit 1 unit 1 unit 1 unit 1 unit 1 unit Start/end of path around the outside Perimeter (P) = 1 + 1 + 1 + 1 + 3 + 1 + 1 + 1 units = 10 units 6 H 9 SERIES TOPIC Area and Perimeter Mathletics ©3P Learning Ltd Area and Perimeter a 1 unit Perimeter = Perimeter = + units + + + + units + units = Write the length of the perimeter (P) for each of these shaded shapes: a b P = 3 + units = 1 unit units + 1 unit c + ...../...../20.... units Perimeter = b + + = 2 S I NG U N I RU T TE Calculate the perimeter of these shaded shapes: RES * PERI ME 1 R E S * P E RI ME S ING U N I RU T Perimeter using unit squares UA TE SQ UA Your Turn SQ How does it work? units c P = units d P = units P = units The shaded shapes in 2 all have the same area of 6 units2. Use your results in question 2 to help you explain briefly whether or not all shapes with the same area have the same perimeter. Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 7 How does it work? Your Turn Area and Perimeter Perimeter using unit squares 4 a Draw six patterns on the grid below which: • all have an area of 5 units2 and, • have a different perimeter from each other. All squares used for each pattern must share at least one common side or corner point 1 unit 1 unit b Draw another five patterns on the grid below which: • all have an area of 5 units2 and, • have a different perimeter than the shapes formed in part a . All squares used for each pattern must share at least half of a common side point . 1 unit 1 unit 8 H 9 SERIES TOPIC Area and Perimeter Mathletics ©3P Learning Ltd or a corner . Where does it work? Area and Perimeter Area: Squares and rectangles A simple multiplication will let you calculate the area of squares and rectangles. For squares and rectangles, just multiply the length of the perpendicular sides (Length and width). Length Width Square Length Width Side (x) Rectangle Side (x) Side (y) Side (x) Area = length # width Area = length # width = Side ^ xh units # Side^ xh units = Side ^ xh units # Side^ yh units = x # x units2 = x # y units2 = x2 units2 = xy units2 Here are some examples involving numerical lengths: Calculate the area of these shaded shapes (i) Area = length # width = 4 units # 4 units = 42 units2 4 units = 16 units2 So why units squared for area? 4 units # 4 units = 4 # 4 units # units = 42 # units2 = 16 units2 Area = length # width (ii) 1.5 mm = 6 mm # 1.5 mm = 9 mm2 Units of area match units of side length 6 mm All measurements (or dimensions) must be written in the same units before calculating the area. Area = length # width (iii) 60 cm 2m = 2 m # 60 cm = 200 cm # 60 cm Write both lengths using the same unit = 12 000 cm2 Units of area match units of side length Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 9 Where does it work? Your Turn Area and Perimeter Area: Squares and rectangles Calculate the area of these squares and rectangles, answering using the appropriate units. a b Area = length d width mm2 3.2 mm Calculate the area of these squares and rectangles. Round your answers to nearest whole square unit. a b Area = km2 # length . Area = width = km2 (to nearest whole km2) . What is the length of this rectangle? Area = 28 units 4 units What are the dimensions of a square with an area of 121 m2? Psst: remember the opposite of squaring numbers is calculating the square root. 10 H 9 SERIES TOPIC Area and Perimeter Mathletics ©3P Learning Ltd ...../...../20.... cm2 # length km2 = 4 7 cm * AREA: SQUARES 1.4 km AND RECTANGLES * AREA: SQUARES 43 mm 3 width = 2 units 2 mm2 # length units2 = m2 Area = 5 mm length width = 0.6 m units2 # m2 # length units2 Area = 3 units Area = width = 2 units c units2 # AND RECTANGLES 1 width cm2 cm2 (to nearest whole cm2) Where does it work? Area and Perimeter Area: Triangles Look at this triangle drawn inside a rectangle. Height (Length) Base (width) The triangle is exactly half the size of the rectangle ` Area of the triangle = half the area of the rectangle units2 = 1 of width (base (b) for a triangle) # Length (height (h) for a triangle) units2 2 = 1 # b # h units2 2 This rule works to find the area for all triangles! Here are some examples involving numerical dimensions: Calculate the area of the shaded triangles below (i) 4 m 5 m Area = 1 2 = 1 2 # base # height #3m #4m Height = use the perpendicular height = 6 m2 6 m The rule also works for this next triangle which is just the halves of two rectangles combined. Area = 1 2 4 mm = 1 2 (ii) # base # height # 5.4 mm # 4 mm Here, we say the height is the perpendicular distance of the third vertex from the base. = 10.8 mm2 5.4 mm For unusual triangles like this shaded one, we still multiply the base and the perpendicular height and halve it. (iii) Area = 1 # base # height 2 = 1 # 1.5 units # 2 units 2 units 2 1.5 units = 1.5 units2 Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 11 Area and Perimeter * A REA S LE a b 4 units ...../...../20.... REA: TRIANG Calculate the area of the triangle that cuts these two shapes in half. G LE S * A R E A : IANGL TR : Area: Triangles 1 IA N TR *A Your Turn ES Where does it work? 8 units 2 units Area = 1 2 # base height # units2 # base units2 = 2 Area = 1 2 units2 # height units2 = Calculate the area of these shaded triangles: a b 14 cm 12 cm 8 mm 12 mm Area = # mm2 # Area = mm2 = # d 7.5 units 4.5 m 10 units Area = # 600 cm # units2 Area = units2 = # Area = 4 m # # 5 m m2 = H 9 SERIES TOPIC Area and Perimeter Mathletics ©3P Learning Ltd # m2 = e 12 cm2 cm2 = c # m2 Remember: same units needed. m2 Where does it work? Area and Perimeter Area: Parallelograms Parallelograms have opposite sides equal in length and parallel (always the same distance apart). Perpendicular height (h) The shortest distance between a pair of parallel sides is called the perpendicular height We can make them look like a rectangle by cutting the triangle off one end and moving it to the other. height Parallelogram Rectangle move triangle cut off ` Area of a parallelogram = Area of the rectangle formed after moving triangle = length # perpendicular height units2 = l # h units2 Calculate the area of these parallelograms (i) Area = length # height 20 mm = 30 mm # 15 mm 15 mm = 450 mm2 30 mm A parallelogram can also be formed joining together two identical triangles. 13 m 12 m (ii) Find the area of the parallelogram formed using two of these right angled triangles: 13 m 5m 12 m 12 m 13 m 13 m Copy and flip both vertically and horizontally 12 m 12 m 5m Parallelogram Area = length # perpendicular height OR # 5 m # 12 m 13 m 5m Bring them together Area = 2 # area of the triangle = 2#1 2 5m 5m 5m = 5 m # 12 m = 60 m2 = 60 m2 Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 13 Your Turn Area and Perimeter G RALLELO Complete the area calculations for these parallelograms: PA M * A R EA : b 10 units Area = units2 Area = height cm2 = b 26 m 10 m 2 mm 24 m Area = 1.6 mm 1.2 mm m2 Area = mm2 Fill the grid below with as many different parallelograms as you can which have an area of 4 units2. 1 unit 1 unit 14 height Calculate the area of the parallelograms formed using these triangles. a 3 cm2 # length units2 = 2 4.6 cm # length 3.9 cm 2.2 cm 4.5 mm G a ...../...../20.... RALLELO 1 PA Area: Parallelograms M * A R EA : RA RA Where does it work? H 9 SERIES TOPIC Area and Perimeter Mathletics ©3P Learning Ltd Where does it work? Area and Perimeter Area of composite shapes When common shapes are put together, the new shape made is called a composite shape. Common shape (Rectangle) + Common shape = Composite shape (Isosceles triangle) (Rectangle + Isosceles triangle) Composite just means it is made by putting together separate parts Just calculate the area of each shape separately then add (or subtract) to find the total composite area. Calculate the area of these composite shapes Split into a triangle (i) 8 cm 10 cm 2 8 cm 1 and a square 2 . Area 1 = 1 2 Area 2 = 8 cm # 8 cm = 64 cm2 # ` Total area = Area 1 2 cm # 8 cm = 8 cm2 1 + Area 2 = 8 cm2 + 64 cm2 2 cm Add area 1 and 2 for the composite area = 72 cm2 8 cm This next one shows how you can use addition or subtraction to calculate the area of composite shapes. (ii) • method 1: Split into two rectangles 3.5 m 8m 7m 3.5 m 4.5 m 3.5 m and Area 1 = 4.5 m # 3.5 m = 15.75 m2 Area 2 = 3.5 m # 7 cm = 24.5 m2 2 ` Total area = 15.75 m2 + 24.5 m2 Add area 1 1 and area 2 together = 40.25 m2 2 7m • method 2: Large rectangle 3.5 m 2 8 m 1 1 7m 4.5 m 1 minus the small 'cut out' rectangle Area 1 = 8 m # 7 m = 56 m2 Area 2 = 3.5 m # 4.5 m = 15.75 m2 ` Total area = 56 m2 - 15.75 m2 2 Subtract area 2 from area 1 = 40.25 m2 Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 15 Where does it work? Your Turn Area and Perimeter Area of composite shapes 1 Complete the area calculations for these shaded shapes: 6 mm a 4 mm Area 1 = mm # mm2 2 mm = 4 mm 2 1 mm Area ` Composite area = 1 2 = mm # mm2 = mm2 2 + mm mm2 = 11 m Area 1 3 m 5 m b = # Area 2 m2 = 6 m m2 # = # m2 m2 = 2 ` Composite area = 3 m 1 5 m 11 m 6 m c 2 cm 6.5 cm Area 1 2.5 cm = 1 = m2 # cm2 Area 2 cm2 = m2 2 + = # # cm2 cm2 = 2 cm 6.5 cm 4 cm ` Composite area = 1 2 - 2.5 cm cm2 cm2 = d 5 m Area 3 m 2 m 5 m 1 2 3 m 16 1 = # 9 SERIES TOPIC Area m2 = ` Composite area = 1 Area and Perimeter Mathletics ©3P Learning Ltd 2 = = 2 - m2 = 2 m H m2 # m2 # m2 m2 Your Turn Area and Perimeter Calculate the area of these composite shapes, showing all working: 13 cm a ...../...../20.... AREA OF COMPOSITE 5 cm 12 cm b Area = cm2 Area = m2 Area = mm2 Area = units2 psst: change all the units to meters first. 300 cm 200 cm 4.5 m c 2 mm d psst: this one needs three area calculations 6 units 10 units 2 SHAPES * AREA OF COMPOSITE Area of composite shapes SHAPES * Where does it work? 5 units Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 17 Where does it work? Area and Perimeter Perimeter of simple shapes By adding together the lengths of each side, the perimeter of all common shapes can be found. Start/finish Start/finish width (y units) Square side (x units) side 2 (y units) Rectangle side 1 (x units) Start/finish length (x units) P = 4 # side length = 4 # x units = 4x units Triangle side 3 (z units) P = width + length + width + length = ^ y + x + y + xh units = ^2 # xh + ^2 # yh units = 2x + 2y units P = side 1 + side 2 + side 3 = x + y + z units You can start/end at any vertex of the shape Here are some examples involving numerical dimensions: Calculate the perimeter of these common shapes (i) 11 units 8 units 11 units Start/finish 10 units 8 units Sum of all the side lengths 10 units Perimeter = 11 units + 8 units + 10 units = 29 units Start/finish (ii) 2.3 cm 2.3 cm 2.3 cm 2.3 cm Four lots of the same side length 2.3 cm Perimeter = 4 # 2.3 cm = 9.2 cm All measurements must be in the same units before calculating perimeter. (iii) The perimeter for parallelograms is done the same as for rectangles. Calculate this perimeter in mm. 15 mm Start/finish 0.5 cm 15 mm 5 mm 5 mm All side lengths in mm 15 mm Perimeter = 2 # 15 mm + 2 # 5 mm = 30 mm + 10 mm = 40 mm 18 H 9 SERIES TOPIC Area and Perimeter Mathletics ©3P Learning Ltd Opposite sides in pairs Where does it work? Your Turn Area and Perimeter Complete the perimeter calculations for these shapes: Perimeter = 17 units 8 units 15 units units + units + units units = Perimeter = 2# b OF SIMPLE SHAPES * a ...../...../20.... PERIMETER Perimeter of simple shapes 1 PERIMETER OF SIMPLE SHAPES * mm + 2 # mm 9 mm mm = 6 mm Perimeter = c m # m = 5m d Perimeter = 2# cm + cm 11 cm cm = 5m 2 Calculate the perimeter of the shapes below, using the space to show all working: a b 15 m 5.8 cm Perimeter = cm Perimeter = c m d 1.6 mm 3 m 1.6 m 2.4 mm Perimeter = 5 m 3.4 m mm Perimeter = Area and Perimeter Mathletics ©3P Learning Ltd 2.4 m m H 9 SERIES TOPIC 19 Where does it work? Your Turn Area and Perimeter Perimeter of simple shapes 3 Find the perimeter of each shape written using the smaller units of measurement in each diagram. a in cm. in mm. b 550 cm 16.5 cm 600 cm 3m 225 mm Perimeter = 4 cm Perimeter = mm Each shape below has its perimeter written inside and is missing one of the side length values. Rule a straight line between each shape and the correct missing side length on the right to answer: How many straight sides does an icosagon have? P = 24 m 8 m F V 5.2 m 4.4 m d P = 12 m a L b E 440 cm S v m H P = 18 m d a v R c a TOPIC 6 m 5 m P = 12 m SERIES 650 cm 1.1 m G Y 9 7 m c T N 6.5 m H 2 m b E 20 380 cm c W P = 14 m 1.6 m 3.5 m T P = 32 m 9 m 2.4 m N b c d Area and Perimeter Mathletics ©3P Learning Ltd m v Where does it work? Area and Perimeter Perimeter of composite shapes The lengths of the unlabeled sides must be found in composite shapes before calculating their perimeter. (3 + 3.5) m = 6.5 m ? m 2 m 2 m 3.5 m 7 m 7 m 3.5 m ? m (7 - 2) m = 5 m Start/finish 3 m 3 m ` Perimeter = 7 m + 6.5 m + 2 m + 3.5 m + 5 m + 3 m = 27 m Here are some more examples. Calculate the perimeter of these composite shapes (i) 9 cm 12 cm 130 mm 5 cm 9 cm 12 cm 13 cm Calculate each side length of the shape in the same units 9 cm + 5 cm = 14 cm ` Perimeter = 9 cm + 13 cm + 14 cm + 12 cm = 48 cm (ii) You can also imagine the sides re-positioned to make the calculation easier 3 m ^6 m - 3 mh ' 2 = 1.5 m 6 m 3 m 3 m 6 m 1.5 m + 1.5 m = 3 m 6 m ` Perimeter = 6 # 1.5 m + 3 m + 6 m ` Perimeter = 2 # 6 m + 2 # 3 m = 18 m = 18 m Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 21 Where does it work? Your Turn Area and Perimeter Perimeter of composite shapes Calculate the value of the sides labeled a and b in each of these composite shapes: 2 cm a b a = cm b b = 8 cm cm 3.4 mm 2.2 mm 1 mm 13 m a b b = mm a = cm b = cm 1.6 mm 15 m d a = 5 cm m 4.8 cm b b = 18 m m a 14 cm b 8 cm 15 cm Calculate the perimeter of these composite shapes: Perimeter = cm # b Perimeter = 2 # a m + 2 # POSITE SH AP m 2 m = m+ 2 1 3 ...../...../20.... R a m C OM OF cm = POSITE SH COM AP OF E 9.8 mm E R I ME T *P E R S E a ERIMET *P E 2 mm a c a a = S 1 m 4 m = Be careful with the units for these next two c Perimeter = 3# 1.2 cm m mm + mm + mm 20 mm = mm Perimeter = # 4.1 cm + 16 mm d 4.1 cm = 38 mm 22 H 9 SERIES TOPIC Area and Perimeter Mathletics Passport © 3P Learning cm # cm Where does it work? Your Turn Area and Perimeter Perimeter of composite shapes Calculate the perimeter of these composite shapes in the units given in square brackets. Show all working. 6mm @ a b 4 mm 2.2 m Perimeter = 3.6 cm mm d 48 mm m 6km @ psst: km m 1.5 km 1200 m Perimeter = cm Perimeter = km Earn an awesome passport stamp for this one! The incomplete geometric path shown below is being constructed using a combination of the following shaped pavers: 1 m 2 m 2 m 1 m 1.41 m 2 m 1 m 1 m E SOM E A WES OME ...../..... /20.... ME S Mathletics Passport © 3P Learning E Area and Perimeter SOM Total perimeter of completed path = AWE Completed path AWE SOM The gap in between each part of the spiral path is always 1 m wide. Calculate what the total perimeter of this path will be when finished. AWE 1.41 m AWE 1 m ESO 4 Perimeter = 22 mm 6cm @ c 6m @ OME AW 3 m H 9 SERIES TOPIC 23 Where does it work? Your Turn Area and Perimeter Perimeter of composite shapes 5 The four composite shapes below have been formed using five, unit squares. a Using your knowledge of perimeter and the grid below, combine all four pieces to create two different shapes so that: • One shape has the smallest possible perimeter. • The other has the largest possible perimeter. All shapes must be connected by at least one whole side of a unit square. 1 unit 1 unit b Briefly describe the strategy you used to achieve each outcome below: • A shape with the smallest possible perimeter. • A shape with the largest possible perimeter. 24 H 9 SERIES TOPIC Area and Perimeter Mathletics ©3P Learning Ltd Where does it work? Area and Perimeter Simple word problems involving area and perimeter Sometimes we can only communicate ideas or problems through words. So it is important to be able to take written/spoken information and turn it into something useful. For example, Miguel wants to paint a square. He has just enough paint to create a line 240 cm long. What is the longest length each side of the square can be if he wishes to use all of the paint? To use up all the paint, the total perimeter of the square must equal 240 cm. So each side length = 240 cm ' 4 = 60 cm ` The longest length each side of the square painted by Miguel can be is 60 cm. This is useful for Miguel to know because if he painted the first side too long, he would run out of paint! Here are some more examples (i) A rectangular park is four times longer than it is wide. If the park is 90 m long, how much area does this park cover? ^90 ' 4h m = 22.5 m Draw diagram to illustrate problem 90 m Area = length # width = 90 m # 22.5 m = 2025 m2 (ii) At a fun run, competitors run straight for 0.9 km before turning left 90 degrees to run straight for a further 1.2 km. The course has one final corner which leads back to the start along a straight 1.5 km long street. How many laps of this course do competitors complete if they run a total of 18 km? 1.2 km 0.9 km 1.5 km Draw diagram to illustrate problem Start/finish Perimeter of course = 0.9 km + 1.2 km + 1.5 km = 3.6 km Perimeter will be the length of each lap ` Length of each lap of the course is 3.6 km ` Number of laps = 18 km ' 3.6 km Race distance divided by the length of each lap =5 ` Competitors must complete 5 laps of the course to finish Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 25 Where does it work? Your Turn Area and Perimeter Simple word problems involving area and perimeter 1 2 3 Three equilateral triangles, each with sides of length 3 cm have been placed together to make one closed four-sided shape. Each triangle shares at least one whole side with another. Calculate the perimeter of the shape formed. a Use all four squares below to make two shapes in which the number of sides is also equal to four. Compare the distance around the outside of your two shapes and explain what this shows us about the relationship between area and perimeter. b You have been employed by a fabric design company called Double Geometrics. Your first task as a pattern maker is to design the following using all seven identical squares: “Closed shapes for a new pattern in which the value of their perimeter is twice the value of their area.” Draw five possible different patterns that match this design request. The base length of a right-angled triangle is one fifth of its height. If the base of this triangle is 4.2 m, calculate the area of the triangle. SIMPLE WORD PROBLEMS INVOLVING AREA AND PERIMETER ...../...../20.... 26 H 9 SERIES TOPIC Area and Perimeter Mathletics ©3P Learning Ltd Where does it work? Your Turn Area and Perimeter Simple word problems involving area and perimeter 4 An architect is asked to design an art gallery building. One of the design rules is that the floor must be a rectangle shape with an area of 64 m2. a If only whole meter measurements can be used, sketch all the different possible floor dimensions. b Another design rule is to try ensure a large perimeter so there is more space to hang paintings from. Use calculations to show which floor plan will have the largest perimeter. c Would the design with the largest possible perimeter be a good choice? Explain briefly why/why not. d A small art piece at the gallery has one side of an envelope completely covered in stamps like the one pictured below. How many of these stamps were needed to cover one side of an envelope 12.5 cm wide and 24.5 cm long if they all fit perfectly without any edges overlapping? 2.5 cm 3.5 cm 12.5 cm 24.5 cm Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 27 Where does it work? Your Turn Area and Perimeter Simple word problems involving area and perimeter 5 A fence used to close off a parallelogram-shaped area is being rearranged to create a square area with the same perimeter. The short side of the area is 34 m long (half the length of the long side). a How long will each side of the new square area be after using the whole length of this fence? 34 m b 6 If the distance between the longer sides of the original area was 30 m and the length did not change, use calculations to show which fencing arrangement surrounded the largest area. A wall is created by stacking equal-sized rectangular bricks on top of each other as shown. The end of each rectangle sits exactly half-way along the long side of the rectangle underneath it. Each brick = 16 cm 28 cm 28 a A 500 mL tin of white paint has been purchased to paint the wall. The instructions on the paint tin say this is enough to cover an area of 11 500 cm2. Use calculations to show that there is enough paint in the tin to cover side of the wall. b If a beetle walked all around the outside of the wall (including along the ground), how many meters did it walk? H 9 SERIES TOPIC Area and Perimeter Mathletics Passport © 3P Learning What else can you do? Area and Perimeter Rhombus and Kite shapes The area for both of these shapes can be calculated the same way using the length of their diagonals. A B • A rhombus is like a square parallelogram. Area = ^diagonal lengths multiplied togetherh ' 2 D = ^ AC # BDh ' 2 C A Rhombus is a parallelogram, so we can also use the same rule to find the area: height Perimeter = 4 # length of one side = 4 # AB B length • A kite has two pairs of equal sides which are adjacent (next to) each other. A Area = ^diagonal lengths multiplied togetherh ' 2 C = ^ AC # BDh ' 2 Perimeter = 2 # short side + 2 # long side = 2 # AB + 2 # AD D Here are some examples: Calculate the area and perimeter of these shapes (i) For this rhombus, WY = 12 cm and XZ = 16 cm. W Area = ^diagonal lengths multiplied togetherh ' 2 X = ^12 cm # 16 cmh ' 2 Z 10 cm = 96 cm2 Y Perimeter = 4 # length of sides = 4 # 10 cm = 40 cm (ii) For the kite ABCD shown below, AC = 4.7 m and BD = 2.1 m. 1.5 m A Area = ^diagonal lengths multiplied togetherh ' 2 B = ^2.1 m # 4.7 mh ' 2 3.7 m D = 4.935 m2 C Perimeter = 2 # short side + 2 # long side = 2 # 1.5 m + 2 # 3.7 m = 10.4 m Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 29 Area and Perimeter PR = 18 cm and QS = 52 cm KITE SHAP E ND b BD = 1.8 mm and AC = 2.4 mm A a 20.... / . . . . . / ..... E Calculate the area and perimeter of these shapes: 1 A KITE SHAP Rhombus and Kite shapes R H O M B US ND S R H O MB U S Your Turn S What else can you do? Q A 41 cm P R B D 15 cm C 3.6 mm S Area = cm2 ' # Area = cm2 = Perimeter = 2# # cm Perimeter = cm 1 mm2 2 mm2 = +2# = # mm # mm = Calculate the perimeter of these composite shapes: 2 a b 14 m 6.5 cm 3.4 cm 5.1 cm 9 m Perimeter = m cm Calculate the area of this composite shape, showing all working when: 3 HL = 30 m, IK = IM = 16 m and JL = 21 m J I H K M 30 Perimeter = L H 9 SERIES TOPIC Area = Area and Perimeter Mathletics ©3P Learning Ltd m2 '2 = # 1 2 What else can you do? Area and Perimeter Trapezoids A trapezoid is a quadrilateral which has only one pair of parallel sides. So the area formula for a trapezoid would also work on all of those shapes. a A B A height (h) C B height (h) D b a C D b Two common trapezoid shapes In both shapes, the sides AB (a) and CD (b) are parallel (AB || CD) . The height is the perpendicular distance between the parallel sides. : Area = ^sum of the parallel sidesh # height ' 2 = ^ a + bh # h ' 2 : Perimeter = AB + BD + CD + AC Here are some examples: Calculate the area and perimeter of these shapes (i) Area = ^sum of the parallel sidesh # height ' 2 20 mm = ^22 mm + 10 mmh # 16 mm ' 2 = 32 mm # 16 mm ' 2 10 mm = 256 mm2 22 mm Perimeter = 20 mm + 22 mm + 16 mm + 10 mm 16 mm (ii) = 68 mm Area = ^sum of the parallel sidesh # height ' 2 6.7 m 2.9 m 2 m 10.1 m = ^6.7 m + 14.5 mh # 2 m ' 2 = 21.2 m # 2 m ' 2 14.5 m = 21.2 m2 Perimeter = 6.7 m + 10.1 m + 14.5 m + 2.9 m = 34.2 m Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 31 Your Turn Area and Perimeter b 1 km 15 km 12.5 m 41 km 9 km 1.8 m 53 km Area = 8.2 m 4.5 m + # Area = ' 2 km2 km2 = = km Perimeter = 2 + # m2 m Perimeter = Use the trapezoid method to calculate the area of these composite plane shapes. a b 8 cm 5 cm 1 mm 2.4 mm 14.3 mm 15 cm Area = 3 cm2 Area = mm2 Use the trapezoid method to calculate the area of this composite plane shapes. 16.7 m 33.4 m 1 2 170 cm 240 cm Area = 32 H 9 SERIES TOPIC ...../...../20.... A a PE Calculate the area and perimeter of these trapezoids: IDS * TR A 1 DS * T R I DS * T R ZO A Trapezoids OIDS * TR A ZO I PE Z PE ZO PE What else can you do? m2 Perimeter = Area and Perimeter Mathletics ©3P Learning Ltd m ' 2 m2 What else can you do? Your Turn Area and Perimeter Area challenge Fill the grid below with as many different squares, triangles, rectangles, parallelograms, rhombi, kites and trapezoids as you can which all have the same area of 8 units2. 1 unit 1 unit Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 33 What else can you do? Your Turn Area and Perimeter Reflection Time Reflecting on the work covered within this booklet: • What useful skills have you gained by learning how to calculate the area and perimeter of plane shapes? • Write about one or two ways you think you could apply area and perimeter calculations to a real life situation. • If you discovered or learnt about any shortcuts to help with calculating area and perimeter or some other cool facts/conversions, jot them down here: 34 H 9 SERIES TOPIC Area and Perimeter Mathletics ©3P Learning Ltd Cheat Sheet Area and Perimeter Here is what you need to remember from this topic on Area and perimeter Area using unit squares Area is just the amount of flat space a shape has inside its edges or boundaries. A unit square is a square with each side exactly one unit of measurement long. Count the total number of whole squares, or fractions of squares to calculate the area. Area (A) = 2 units2 Perimeter using unit squares The perimeter with unit squares means count the number of edges around the outside of the shape. Perimeter (P) = 6 units Area: Squares and rectangles Just multiply the length of the perpendicular sides (length and width). length width Square length side (x) width side (y) Rectangle side (x) side (x) Area = length # width Area = length # width = x2 units2 = xy units2 height Area: Triangles height height base base base ` Area of the triangle = (half the base multiplied by the perpendicular height) units2 = 1 # b # h units2 2 Area: Parallelograms Perpendicular height (h) Length (l) ` Area of a parallelogram = length # perpendicular height units2 = l # h units2 Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 35 Cheat Sheet Area and Perimeter Area of composite shapes 1 2 Area 1 (Rectangle) + 1 + 2 Area 2 = (Isosceles triangle) Composite Area = Area 1 + Area 2 (Rectangle + Isosceles triangle) Perimeter of simple shapes Add together the lengths of every side which make the shape. Start/finish Start/finish width (y units) Square side 2 (y units) Rectangle side (x units) side 1 (x units) Start/finish length (x units) P = side 1 + side 2 + side 3 = x + y + z units P = width + length + width + length = 2x + 2y units P = 4 # side length = 4x units Triangle side 3 (z units) Perimeter of composite shapes The lengths of all unlabeled sides must be found in composite shapes before calculating their perimeter. It is easier to add them together if the lengths are all in the same units. (3 + 3.5) m = 6.5 m ? m 2 m 2 m 3.5 m 7 m 3.5 m 7 m ? m (7 - 2) m = 5 m Start/finish 3 m 3 m ` Perimeter = 7 m + 6.5 m + 2 m + 3.5 m + 5 m + 3 m = 27 m B Rhombus, Kites and Trapezoids A B A C A a B perpendicular height (h) D Rhombus Area = ^ AC # BDh ' 2 Perimeter = 4 # AB 36 C C H 9 SERIES TOPIC D Kite b a A B perpendicular height (h) D C b Trapezoid Area = (AC # BD) ' 2 Perimeter = 2 # AB + 2 # AD Area and Perimeter Mathletics ©3P Learning Ltd Area = (a + b) # h ' 2 Perimeter = AB + BD + CD + AC D Answers Area and Perimeter Area using unit squares Area using unit squares 4. Here are 42 solutions. There are more... 1. a Area = 4 whole squares = 4 units2 b Area = 6 whole squares = 6 mm2 c Area = 2 whole + 2 half squares = 2 m2 + 2 # 1 m2 2 = 3 m2 d Area = 4 whole + 4 half squares = 4 units2 + 4 # 1 units2 2 = 6 units2 e Area = 2 whole + 4 quarter squares = 2 units2 + 4 # 1 units2 4 = 3 units2 f Area = 4 whole + 2 quarter squares = 4 cm2 + 2 # 1 cm2 4 = 4.5 cm2 g Area = 3 whole + 4 half + 4 quarter squares = 3 units2 + 4 # 1 units2 + 4 # 1 units2 2 4 = 6 units2 2. a Area = 9 cm2 c Area = 6 m2 e Area = 5 units g Area = 12.5 km 3. a c 2 2 b Area = 12 units2 d Area = 4.5 mm2 f Area = 8 mm h Area = 14 cm 2 Perimeter using unit squares 1. 2 b 2. d 3. a Perimeter = 2 + 2 + 2 + 2 units = 8 units b Perimeter = 1 + 3 + 1 + 3 units = 8 units c Perimeter = 2 + 1 + 1 + 1 + 1 + 2 units = 8 units a P = 10 units a P = 12 units c P = 14 units d P = 13 units Even though the shapes all have the same area, they do not all have the same perimeter lengths. This shows that the shapes with the same area will not necessarily have the same perimeter. So the perimeter is not related to the area of the shape. Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 37 Answers Area and Perimeter Perimeter using unit squares Area: Triangles 1 # 2 # 4 units2 1. a Area = 2 = 4 units2 4. a b P = 10 units P = 12 units P = 14 units Area = 1 # 8 # 8 units2 2 = 32 units2 1 2 # 12 # 8 mm 2. a Area = 2 = 48 mm2 P = 16 units P = 18 units P = 20 units Area = c Area = d Area = e Area = b P = 11 units P = 13 units P = 17 units 1 2 # 14 # 12 cm 2 = 84 cm2 b 1 2 # 10 # 7.5 units 2 = 37.5 units2 P = 15 units P = 19 units 1 2 # 6 # 4.5 m 2 = 13.5 m2 1 2 #5#4m 2 = 10 m2 Area: Squares and rectangles Area: Parallelograms 1. a Area = 2 # 2 units2 = 4 units2 b Area = 0.6 # 0.6 m2 = 0.36 m2 Area = 3 # 2 units2 = 6 units2 d Area = 5 # 3.2 mm2 = 16 mm2 c 2. a Area = 1.4 # 1.4 km2 = 1.96 km2 . 2 km2 (to nearest whole km2) b 1. a Area = 4.5 # 10 units2 b Area = 4.6 # 2.2 cm2 = 450 units2 = 10.12 cm2 2. a Area = 240 m2 3. Area = 7 # 4.3 cm2 = 30.1 cm2 . 30 cm2 (to nearest whole cm2) 3. The length of the rectangle is 7 units. 4. The length of each side is 11 units 38 H 9 SERIES TOPIC Area and Perimeter Mathletics ©3P Learning Ltd b Area = 1.92 mm2 Answers Area and Perimeter Area of composite shapes 1. a Area 1 = 4 mm # 4 mm = 16 mm2 Area 2 = 2 mm # 2 mm = 4 mm2 Perimeter of simple shapes 2. a Perimeter = 23.2 cm Area 1 = 0.5 # 6 # 8 m2 = 24 m2 Area 2 = 11 # 5 m2 = 55 m2 4. Area 1 = 6.5 # 2 cm2 = 13 cm2 Area 2 = 0.5 # 4 # 2 cm2 = 4 cm2 W E N T Y a b c d m v c a = 9 m b = 6 m b a = 1.8 mm b = 2.2 mm d a = 5.2 cm b = 11.2 cm 5 # 9.8 cm 2. a Perimeter = = 49 cm b Perimeter = 2 # a m + 2 # 2 m = 12 m + 4 m = 16 m = 2 # 2 m2 = 4 m2 c Perimeter = 3 # 12 mm + 20 mm + 16 mm = 72 mm Composite area = 20 - 4 m2 = 16 m2 d Perimeter = 4 # 4.1 cm + 2 # 3.8 cm = 24 cm Area 1 = 0.5 # 8 # 5 m2 = 20 m2 Area 2 2. a Area = 199 cm2 c Perimeter = 10.8 m T 1. a a = 4 cm b = 5 cm Composite area = 13 - 4 cm2 = 9 cm2 d d Perimeter of composite shapes Composite area = 24 + 55 m2 = 79 m2 c Perimeter = 45 m 3. a Perimeter = 1450 cm b Perimeter = 780 mm Composite area = 16 + 4 mm2 = 20 mm2 b Perimeter = 8 mm c b Area = 32 mm 2 b Area = 22.5 m2 d Area = 90 units 48 mm 3. a Perimeter = 2 Perimeter of simple shapes c Perimeter = 21.2 cm b Perimeter = 26.4 m d Perimeter = 6.6 km 4. Total perimeter of completed path = 132 m 1. a Perimeter = 15 units + 17 units + 8 units = 40 units b Perimeter = 2 # 9 mm + 2 # 6 mm = 30 mm c Perimeter = 4#5m = 20 m d Perimeter = 2 # 11 cm + 5 cm = 27 cm Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 39 Answers Area and Perimeter Simple word problems involving area and perimeter Perimeter of composite shapes 5. a 2. b Smallest possible perimeter = 18 units 3. Area of a triangle = 44.1 m2 Largest possible perimeter = 40 units b c 4. a 1 Try to make as many sides as possible touching each other, which reduces the number of sides that are counted for the perimeter. 64 m 2 Making each shape joined to the other by one side only, which increases the number of sides that must counted for the perimeter. 4 Perimeter = 15 cm Shape 2 2 Perimeter = 40 m 3 Perimeter = 68 m 4 Perimeter = 32 m 1 has the largest perimeter No, floor plan 1 would not be a good choice. While it meets the rule of having the largest possible perimeter, it would be very long and too narrow for more than one person to walk through at a time. d Total number of stamps that fit = 35 stamps 5. a Each side of the new square area = 51 m long Perimeter = 8 units b The area of both shapes is the same, but the perimeters are different. This shows that there is no relationship between the area and the perimeter of a shape. The new square shape will surround more area. 6. a There will be just enough paint to cover the side of the wall (with 300 cm2 to spare) b TOPIC Perimeter = 130 m c Perimeter = 10 units SERIES 16 m 1 Floor plan Shape 1 9 4 m 8 m 1. H 3 8 m b 40 2 m 32 m Simple word problems involving area and perimeter 2. a 1 m The beetle walked a total distance of 5.52 m Area and Perimeter Mathletics ©3P Learning Ltd Answers Area and Perimeter Rhombus and Kite shapes Trapeziums 1. a Area = 18 # 52 ' 2 cm2 = 468 cm2 b c d 1. a Area = (53 + 1) # 9 ' 2 km2 = 243 km2 Perimeter = 110 km Area = 1.8 # 2.4 # 1 mm2 2 = 2.16 mm2 b Perimeter = 2 # 41 + 2 # 15 cm = 112 cm Perimeter = 27 m Perimeter = 4 # 3.6 mm = 14.4 mm 64 m 2. a Perimeter = b Area = (4.5 + 12.5) # 1.8 ' 2 m2 = 15.3 m2 135 cm2 2. a Area = Perimeter = 31.7 cm 53.35 m2 3. Area = b Area = 24.12 mm2 Perimeter = 74 m 408 m2 3. Area = Area challenge Here are 20 possible shapes which all have an area of 8 units2 . There are many more. Area and Perimeter Mathletics ©3P Learning Ltd H 9 SERIES TOPIC 41 Notes 42 Area and Perimeter H 9 SERIES TOPIC Area and Perimeter Mathletics ©3P Learning Ltd Area and Perimeter www.mathletics.com H SERIES
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