Practice Test - Chapter 5
1. MULTIPLE CHOICE The rectangle below has a length of 20 centimeters and a perimeter of P centimeters.
Which equation could be used to find the width of the rectangle?
A P = 40 +
B P = 40 + 2w
C P = 40 + w
D P = 20 + 2w
SOLUTION: The rectangle has a length of 20 centimeters and a perimeter of P centimeters.
Let w = the width of the rectangle.
P = 2l + 2w
P = 2(20) + 2w
P = 40 + 2w
Choice B is the correct answer.
2. MEASUREMENT If the length of the side of each square is 6 units, what is the perimeter and area of the
rectangle?
SOLUTION: The length of the rectangle is made up of 4 square lengths. Each square length is 6 units, so the length of the
rectangle is 4 • 6 units. The width is one square length, or 6 units.
The perimeter is 60 units.
The area is 144 square units.
Solve each equation. Check your solution.
3. 61 = 3b + 7
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Check:
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Practice Test - Chapter 5
The area is 144 square units.
Solve each equation. Check your solution.
3. 61 = 3b + 7
SOLUTION: Check:
4. –27 + 15x = 33 – 9x
SOLUTION: Check:
5. 16y + 24 = –18 + 9y
SOLUTION: Check:
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Practice Test - Chapter 5
5. 16y + 24 = –18 + 9y
SOLUTION: Check:
6. 7(m + 6) = 105
SOLUTION: Check:
7. s – 17 = 7(s – 5)
SOLUTION: Check:
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8. 9(12 + 4z) = 3(6z – 18)
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Practice Test - Chapter 5
7. s – 17 = 7(s – 5)
SOLUTION: Check:
8. 9(12 + 4z) = 3(6z – 18)
SOLUTION: Check:
9. PROJECTS The eighth grade class is making digital yearbooks on a DVD. One company charges a rate of $235
plus an additional $0.75 per DVD. Another company charges $125 plus $1.63 per DVD. Write and solve an equation
to determine for what number of DVDs the costs will be equal.
SOLUTION: Let d = the number of DVDs.
The first company charges a rate of $235 plus an additional $0.75 per DVD. The cost for the first company is C =
235 + 0.75d.
The second company charges a rate of $125 plus $1.63 per DVD. The cost for the second company is C = 125 +
2.63d.
Set the cost for the first company equal to the cost for the second company and solve for d..
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Practice Test - Chapter 5
9. PROJECTS The eighth grade class is making digital yearbooks on a DVD. One company charges a rate of $235
plus an additional $0.75 per DVD. Another company charges $125 plus $1.63 per DVD. Write and solve an equation
to determine for what number of DVDs the costs will be equal.
SOLUTION: Let d = the number of DVDs.
The first company charges a rate of $235 plus an additional $0.75 per DVD. The cost for the first company is C =
235 + 0.75d.
The second company charges a rate of $125 plus $1.63 per DVD. The cost for the second company is C = 125 +
2.63d.
Set the cost for the first company equal to the cost for the second company and solve for d..
The costs will be equal when the number of DVDs is 125.
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