Unit 2: Graphing Equations Lesson 5: Graphing Using Slope Intercept Form Notes Example 1 Slope = ________ Y-intercept = __________ Copyright© 2009 Algebra-class.com Example 2 Slope = ________ Y-intercept = __________ Unit 2: Graphing Equations Example 3 Example 4 Copyright© 2009 Algebra-class.com Unit 2: Graphing Equations Lesson 5: Using Slope Intercept Form to Graph Equations Directions: Graph each equation using the following directions: Example: 1. Circle the y-intercept in the equation. y = 1/2x +2 Then plot this point on your graph. (0,2) 2. Put a square around the slope in the equation. Then use the slope to plot your next point. y = ½ x +2 Rise = 1 (up 1) Run 2 (right 2) 3. Draw a line through your two points. Copyright© 2009 Algebra-class.com Unit 2: Graphing Equations 1. 3. y = 2x +2 y = 1/3x - 4 Copyright© 2009 Algebra-class.com 2. y = -3x +1 4. y = -2/5x - 2 Unit 2: Graphing Equations 5. 7. y = -3/4x y = -2 Copyright© 2009 Algebra-class.com 6. y = x +5 8. y = -4x Unit 2: Graphing Equations 9. Which graph represents the equation: y = -2/3x – 7? A. Line A B. Line B C. Line C D. Line D 10. Graph the equation: y = 3x -8 on the grid. Label this line A. Identify three solutions for this equation. 11. Graph the equation: y = -x +10 on the grid. Label this line B. Identify three solutions for this equation. Copyright© 2009 Algebra-class.com Unit 2: Graphing Equations 1. Which line on the graph represents the equation: y = -3/4x – 2? (1 point) A. Line A B. Line B C D C. Line C D. Line D B A Part 2: Identify the slope and y-intercept in each equation. Then graph the equation on the grid. (3 points each) 1. y = 3x -6 2. y = -1/4x Slope: _______ Slope: __________ Y-intercept:_________ Y-intercept:___________ Copyright© 2009 Algebra-class.com Unit 2: Graphing Equations Lesson 5: Using Slope Intercept Form - Answer Key 1. 3. y = 2x + 2 y = 1/3x - 4 Copyright© 2009 Algebra-class.com 2. y = -3x +1 4. y = -2/5x - 2 Unit 2: Graphing Equations 5. y = -3/4x **The y-intercept is (0,0). When no number is written in the y-intercept’s place, it is assumed to be 0. 7. y = -2 **There is no variable term in this equation; therefore the slope is 0. Anytime the slope is 0, the line is horizontal. Therefore, we have a horizontal line through the y-intercept. Copyright© 2009 Algebra-class.com 6. y= x +5 **The slope is 1. When there is no coefficient (slope), the slope is assumed to be 1. (1 times x is still x) 8. y = -4x **The y-intercept is (0,0). When no number is written in the y-intercept’s place, it is assumed to be 0. Unit 2: Graphing Equations 9. Which graph represents the equation: y = -2/3x – 7? A. Line A B. Line B C. Line C D. Line D Since the equation has a slope of -2/3, you can eliminate C and D because both lines have a positive slope (rising from left to right.) The equation y = -2/3x – 7 has a y-intercept of -7. Therefore, letter B, must be the correct answer because the line passes through the point (0, -7). Letter B has a slope of -2/3. 10. Graph the equation: y = 3x -8 on the grid. Label this line A. Identify three solutions for this equation. Possible solutions: (4,4) (3,1) (2,-2) (1,-5) (0,-8) (Or any point on the line) 11. Graph the equation: y = -x +10 On the grid. Label this line B. Identify three solutions for this equation. Possible solutions: (0,10) (1,9) (2,8) (3,7) (4,6) (Or any point on the line) Copyright© 2009 Algebra-class.com y-intercept = -7 Unit 2: Graphing Equations 1. Which line on the graph represents the equation: y = -3/4x – 2? (1 point) A. Line A B. Line B C D C. Line C D. Line D B A Line B has a y-intercept of -2. The slope is -3/4, so if you count down three and right 4, you will end up on the next point on the line. The slope is negative, so you can immediately eliminate letter D since its slope is positive. Part 2: Identify the slope and y-intercept in each equation. Then graph the equation on the grid. (3 points each) 1. y = 3x -6 2. y = -1/4x +0 Slope: 3 Slope: -1/4 Y-intercept: -6 Y-intercept: 0 (this is the origin) Copyright© 2009 Algebra-class.com
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