Any equation whose largest exponent is 2 is a quadratic equation. Already factored. x + 1 = 0 or x - 2 = 0 x = -1 or x = 2 Just set each factor equal to 0 and solve. x = 0 or x - 3 = 0 x =0 or x = 3 1 3x2 + 3x + 1 = -x y2 - 3y + 2 = 0 3x2 + 3x + x + 1 = 0 (y - 1)(y - 2) = 0 y - 1 = 0 or y - 2 = 0 y =1 or y = 2 Remember that you can check your answers using LS/RS. 2t2 + 11t + 5 = 0 2t2 + 10t + t + 5 = 0 2t(t + 5) + 1(t + 5) = 0 2(5x2 - 8x + 3) = 0 P = 2 x 5 = 10 S = 11 3x(x + 1) + 1(x + 1) = 0 (x + 1)(3x + 1) = 0 2y2 - 3y - 2 = 0 2y - 4y + y - 2 = 0 2 P = 2 x (-2) = -4 S = -3 2y(y - 2) + 1(y - 2) = 0 (y - 2)(2y + 1) = 0 -1 y = 2 or y = 2 P = 5 x 3 = 15 S = -8 2[5x2 - 5x - 3x + 3] = 0 2[5x(x - 1) - 3(x - 1)] = 0 2(x - 1)(5x - 3) = 0 x = 1 or x = 3 5 S= 4 3x + 3x + x + 1 = 0 2 x + 1 = 0 or 3x + 1 = 0 -1 x = -1 or x = 3 (t + 5)(2t + 1) = 0 t = -5 or t = -1 2 10x2 - 16x + 6 = 0 P =3x 1=3 3x2 + 4x + 1 = 0 n(5n - 8) = 0 n = 0 or 5n - 8 = 0 8 n = 5 2
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