Regents Exam Questions A.A.23: Transforming Formulas 1
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A.A.23: Transforming Formulas 1: Solve literal equations for a given variable
1 Which equation is equivalent to 3x  4y  15?
15  3x
1) y 
4
3x  15
2) y 
4
3) y  15  3x
4) y  3x  15
5 If x  2a  b 2 , then a equals
x  b2
1)
2
2)
3)
4)
x  b2
2
2
b x
2
x  b2
2 The equation P  2L  2W is equivalent to
P  2W
1) L 
2
P  2W
2) L 
2
P
3) 2L 
2W
4) L  P  W
6 If 2m  2p  16, p equals
1) 8  m
2) 16  m
3) 16  2m
4) 9m
3 If 3ax  b  c, then x equals
1) c  b  3a
2) c  b  3a
cb
3)
3a
bc
4)
3a
7 In the equation A  p  prt , t is equivalent to
A  pr
1)
p
Ap
2)
pr
A
p
3)
pr
A
 pr
4)
p
4 If bx  2  K , then x equals
K
1)
2
b
K2
2)
b
2K
3)
b
K2
4)
b
8 If c  2m  d , then m is equal to
cd
1)
2
c
2)
d
2
d
3) c 
2
4) d  2c
1
Regents Exam Questions A.A.23: Transforming Formulas 1
Name: ________________________
www.jmap.org
13 Sean knows the length of the base, b, and the area,
A, of a triangular window in his bedroom. Which
formula could he use to find the height, h, of this
window?
1) h  2A  b
A
2) h 
2b
3) h  (2A)(b)
2A
4) h 
b
ey
 k  t , what is y in terms of e, n, k, and t?
n
tn  k
1) y 
e
tn  k
2) y 
e
n(t  k)
3) y 
e
n(t  k)
4) y 
e
9 If
14 The formula for the volume of a right circular
cylinder is V   r 2 h . The value of h can be
expressed as
V 2
r
1)
10 The members of the senior class are planning a
dance. They use the equation r  pn to determine
the total receipts. What is n expressed in terms of r
and p ?
1) n  r  p
2) n  r  p
p
3) n 
r
r
4) n 
p

2)
3)
4)
V
 r2
 r2
V
V   r2
15 A formula used for calculating velocity is
1
v  at 2 . What is a expressed in terms of v and t?
2
2v
1) a 
t
2v
2) a  2
t
v
3) a 
t
v
4) a  2
2t
11 The formula for potential energy is P  mgh , where
P is potential energy, m is mass, g is gravity, and h
is height. Which expression can be used to
represent g?
1) P  m  h
2) P  mh
P
3)
h
m
P
4)
mh
12 If the formula for the perimeter of a rectangle is
P  2l  2w , then w can be expressed as
2l  P
1) w 
2
P  2l
2) w 
2
Pl
3) w 
2
P  2w
4) w 
2l
2
Regents Exam Questions A.A.23: Transforming Formulas 1
Name: ________________________
www.jmap.org
20 If a  ar  b  r, the value of a in terms of b and r
can be expressed as
b
1
1)
r
1b
2)
r
br
3)
1r
1b
4)
rb
x a
  0, b  0, then x is equal to
4 b
a
1) 
4b
a
2)
4b
4a
3) 
b
4a
4)
b
16 If
21 If 2ax  5x  2, then x is equivalent to
2  5a
1)
2a
1
2)
a5
2
3)
2a  5
4) 7  2a
17 If 9x  2a  3a  4x, then x equals
1) a
2) a
5a
3)
12
a
4)
13
18 If x  y  9x  y , then x is equal to
1) y
1
y
2)
5
3) 0
4) 8
22 Solve for c in terms of a and b: bc  ac  ab
23 Solve: (a  x)(b  x)  x 2
24 Shoe sizes and foot length are related by the
formula S  3F  24, where S represents the shoe
size and F represents the length of the foot, in
inches.
a Solve the formula for F.
b To the nearest tenth of an inch, how long is the
1
foot of a person who wears a size 10 shoe?
2
19 If 7x  2a  3x  5a , then x is equivalent to
7a
1)
10
7a
2)
4
3a
3)
10
3a
4)
4
3
ID: A
A.A.23: Transforming Formulas 1: Solve literal equations for a given variable
Answer Section
1 ANS: 1
REF: 080722a
2 ANS: 1
REF: 010310a
3 ANS: 3
3ax  b  c
3ax  c  b
x
cb
3a
REF: 080808ia
4 ANS: 4
REF: 010116a
5 ANS: 2
REF: 060219a
1
ID: A
6 ANS: 1
REF: 080218a
7 ANS: 2
REF: 010620a
8 ANS: 1
REF: 060719a
9 ANS: 4
ey
k  t
n
ey
 tk
n
y
n(t  k)
e
REF: 011125ia
10 ANS: 4
11 ANS: 4
P  mgh
g
REF: 011016ia
P
mh
REF: 010710a
2
ID: A
12 ANS: 2
P  2l  2w
P  2l  2w
P  2l
w
2
REF: 010911ia
13 ANS: 4
REF: 010517a
14 ANS: 2
REF: 060617a
15 ANS: 2
16 ANS: 4
REF: 061023ia
REF: 080530a
17 ANS: 4
REF: 010011a
3
ID: A
18 ANS: 3
REF: 060310a
19 ANS: 4
REF: 060513a
20 ANS: 3
a  ar  b  r
a(1  r)  b  r
a
br
1r
REF: 060913ia
21 ANS: 3
REF: 010421a
22 ANS:
bc  ac  ab
c(b  a)  ab
c
ab
ba
REF: 081131ia
23 ANS:
ab
ab
REF: 039008al
4
ID: A
24 ANS:
S  24
, 11.5.
3
.
REF: 069922a
5