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Answer - Assignment Expert

Answer on Question #43016 – Physics - Mechanics | Kinematics | Dynamics
A car moves 30m north and then 40m east then what is the magnitude of
displacement of the car?
Solution:
𝑆1 = 30 π‘š βˆ’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘‘β„Žπ‘Žπ‘‘ π‘π‘Žπ‘Ÿ β„Žπ‘Žπ‘  π‘‘π‘Ÿπ‘Žπ‘£π‘’π‘™π‘™π‘’π‘‘ π‘›π‘œπ‘Ÿπ‘‘β„Ž;
𝑆2 = 40 π‘š βˆ’ π‘‘π‘–π‘ π‘‘π‘Žπ‘›π‘π‘’ π‘‘β„Žπ‘Žπ‘‘ π‘π‘Žπ‘Ÿ β„Žπ‘Žπ‘  π‘‘π‘Ÿπ‘Žπ‘£π‘’π‘™π‘™π‘’π‘‘ π‘’π‘Žπ‘ π‘‘;
From the rigth triangle ABC using the Pythagorean Theorem:
𝐷2 = 𝑆12 + 𝑆22
𝐷 = βˆšπ‘†12 + 𝑆22 = √(30 π‘š)2 + (40 π‘š)2 = 50 π‘š
Answer: the magnitude of displacement of the car is equal to 50 m.
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