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Isotopes and Average Atomic Mass -Solutions
How could a scientist test to separate isotopes of the same element? Isotopes of the same element would
have different masses, so they could be separated by mass.
FILL IN THE TABLE.
Nuclear Symbol
# or Protons
# of Neutrons
Mass #
Sulfur-25
6
6
6
24
24
7
7
16
16
6
7
8
34
39
8
13
7
9
12
13
14
58
63
15
20
23
25
Sodium-12
11
1
12
πŸπŸ‘
πŸπŸπ‘΅π’‚
Sodium-13
11
2
13
πŸπŸπŸ‘
πŸ“πŸ“π‘ͺ𝒔
𝟏𝟏𝟏
πŸ“πŸ“π‘ͺ𝒔
πŸπŸŽπŸ‘
πŸ“πŸ‘π‘°
𝟏𝟏𝟏
πŸ“πŸ‘π‘°
πŸ‘πŸ
πŸπŸ“π‘·
Cesium-113
58
Cesium-111
55
55
Iodine - 103
53
56
50
Iodine - 111
53
58
113
111
103
111
Phosphorus - 111
15
17
32
𝟏𝟐
πŸ”π‘ͺ
πŸπŸ‘
πŸ”π‘ͺ
πŸπŸ’
πŸ”π‘ͺ
πŸ“πŸ–
πŸπŸ’π‘ͺ𝒓
πŸ”πŸ‘
πŸπŸ’π‘ͺ
πŸπŸ“
πŸ•π‘΅
𝟐𝟎
πŸ•π‘΅
πŸπŸ‘
πŸπŸ”π‘Ί
πŸπŸ“
πŸπŸ”π‘Ί
𝟏𝟐
πŸπŸπ‘΅π’‚
Hyphen Notation
Carbon-12
Carbon-13
Carbon-14
Chromium-58
Chromium-63
Nitrogen-15
Nitrogen-20
Sulfur-23
Calculating Average Atomic Mass
1. The natural abundance of Boron isotopes is : 19.9 % B-10 and 80.1% B – 11 Calculate the atomic mass of boron.
Create a table as shown in the example above. Include units with your numbers. (10.80 amu)
Isotope
Mass
% (as decimal)
Subtotal
B-10
10
.199
1.99
B-11
11
.801
8.81
Average Atomic Mass =
10.80
2. The natural abundance of Gallium isotopes is : 60.11 % Ga-69 and 39.89% Ga – 71. Calculate the atomic
mass of Gallium. . Include units with your numbers. (69.8 amu)
Ga - 69
Ga - 71
%
0.6011
0.3989
Mass
69
71
Total ->
Subtotal
41.4759
28.3219
69.7978
HERE ARE SOME MORE
3.
Mass #
24
25
26
%
0.7899
0.1
0.1101
Total ->
18.9576
2.5
2.8626
24.3202
4.
Mass
27.97693
28.9765
29.97377
%
0.9223
0.0467
0.031
Total ->
25.80312
1.353202
0.929187
28.08551
5. HERE IS A MORE CHALLENGING QUESTION REQUIRING SOME ALGEBRA
The atomic mass of Cu is 63.540 amu. It is composed of two isotopes, Cu-63 and Cu-65, with atomic masses of
62.930 and 64.928. What is the % abundance of these isotopes?
Since the total % Abundance = 100% an equation between the two can be written as
X + Y = 100 , assign X = % Abundance of Cu-63 and Y = % Abundance of Cu-65
So Y = 100 – X
63.540 = (63 X) + (65 Y) but this has two unknowns so it cant be solved. Yes, it can if Y = 100 – X is used as
follows:
63.540 = (63 X) + (65(1.00-X)) now solve for X
63.540 = 63X + 65-65X
Now collect the X terms and constants:
Now collect the constants: -1.46 = -2X
63.540 = 65-2X
Divide both sides by -2 which gives the value of X
𝑿=
The other percent 100 – 73 = 27%
βˆ’πŸ. πŸ’πŸ”
=. πŸ•πŸ‘
βˆ’πŸ
6. In Column D labeled Subtotals Write the Equations (as EXCEL would need them) for calculating the
Average Atomic Mass in the spreadsheet below. Remember that Equations start with_________. No numbers
are needed for an algebraic solution.
7. CONCEPTUAL QUESTION - Silver has an atomic mass of 107.868 amu. Does any atom of any isotope of silver
have a mass of 107.868 amu? Explain why.
No, no isotope of silver will likely have a mass of 107.868 amu. The atomic mass
reported on the Periodic table is an average. This is similar to taking the average
height of students in a classroom. The average represents the group, not any
individual.
Relative Mass of Subatomic Particles
What are the masses of the various items below?
Mass of Electron (kg)
Mass of Neutrons (kg)
-31
9.1 x 10
kg
1.7 x 10
-27
Calculate the mass of the Neutron Relative to the Electron
Mass of Protons(kg)
1.7 x 10-27 kg
kg
π‘€π‘Žπ‘ π‘  π‘œπ‘“ π‘π‘’π‘’π‘‘π‘Ÿπ‘œπ‘›
π‘€π‘Žπ‘ π‘  π‘œπ‘“ πΈπ‘™π‘’π‘π‘‘π‘Ÿπ‘œπ‘›
=:
π‘€π‘Žπ‘ π‘  π‘œπ‘“ π‘π‘’π‘’π‘‘π‘Ÿπ‘œπ‘› 1.7 π‘₯10βˆ’27 π‘˜π‘”
=
= 1.87 × 103
π‘€π‘Žπ‘ π‘  π‘œπ‘“ πΈπ‘™π‘’π‘π‘‘π‘Ÿπ‘œπ‘› 9.1 π‘₯10βˆ’31 π‘˜π‘”
Calculate the mass of the Proton Relative to the Electron :
π‘€π‘Žπ‘ π‘  π‘œπ‘“ π‘π‘’π‘’π‘‘π‘Ÿπ‘œπ‘› 1.7 π‘₯10βˆ’27 π‘˜π‘”
=
= 1.87 × 103
π‘€π‘Žπ‘ π‘  π‘œπ‘“ πΈπ‘™π‘’π‘π‘‘π‘Ÿπ‘œπ‘› 9.1 π‘₯10βˆ’31 π‘˜π‘”
The proton and neutron are nearly 2000 times more massive than the electron.
This means the electrons mass is insignificant in the mass of an atom. Below you
will see the % of mass contained in an atom’s electrons is very small.
How do the masses of the proton and neutron compare to one another?
The mass of the proton and neutron are nearly the same.
HOW IS MASS DISTRIBUTED IN AN ATOM? Using Helium-3, you will calculate the % of mass from each type of
particle: protons, neutron and electronsType equation here.
Protons
Neutrons
Electrons
πŸ‘
πŸ‘
πŸ‘
# in πŸπ‘―π’† = 𝟐
# in πŸπ‘―π’† = 𝟏
# in πŸπ‘―π’† = 𝟐
Mass of each proton
Mass of each neutron
Mass of each electron
Mass of protons =
Mass of neutrons =
Mass of electrons =
3.4 x 10
3.4 x 10
18.2 x 10
-27
kg
-27
kg
-31
kg
% of mass which is protons
% of mass which is neutrons
% of mass which is electrons
67 %
33 %
0%
Most of the mass of an atom comes from the protons .
Total Mass (add up the row)
5.1 x 10-27 kg