September 19, 2016
• 3.2 Motion with Constant Acceleration
• constant acceleration = velocity changes at a
constant rate
vf = vi + at
d = vit + _12 at2
d = _1 (v + v )t
2
i
vf2 = vi2 + 2ad
f
September 19, 2016
Practice problems P 69 # 16
A golf ball rolls up a hill toward a miniature-golf hole. Assume
that the direction toward the hole is positive.
a) If the golf ball starts with a speed of 2.0 m/s and slows at a
constant rate of 0.50m/s2, what is its velocity after 2.0 s?
b) What is the golf ball's velocity if the constant acceleration
continues for 6.0 s?
September 19, 2016
P 70 # 25
A car accelerates at a constant rate from 15 m/s to 25 m/s while it
travels a distance of 125 m. How long does it take to achieve this
speed?
September 19, 2016
Practice problem P 74 # 29
A man runs along the path shown in Figure 17. From point A to point
B, he runs at a forward velocity of 4.5 m/s for 15 minutes. From point
B to point C, he runs up a hill. He slows down at a constant rate of
0.05m/s2 for 90.0 s and comes to a stop. How far did he run?
Glencoe Physics 2013
September 19, 2016
Homework:
P 69 # 17,18
P 70 # 25,26
P 74 # 28, 30, 34
P 83 # 65,67