VOL. 21, NO. 5 CHINESE JOURNAL OF PHYSICS OVOBER 1989 The Second Area-Weighted Moment of Convex Polygons K. Y. Lin ( ;fst; X $Q ) Department of Physics, National Tsing Hua University Hsinchu, Taiwan 30043 (Received Sep. 14, 1989) The generating function for the second area-weighted moment of the number of convex polygons on the square lattice is derived. The empirical formula of Enting and Guttmann is verified. 1. 1NTRODUCTlON A self-avoiding walk on a periodic lattice has been used as a model of linear polymers1 A self-avoiding loop is a self-avoiding walk returning to the starting point. One of the unsolved problems in Statistical Physics is to derive a generating function for the total number of self-avoiding loops on a square lattice with a fixed length of perimeter. A convex polygon on a square lattice is a special case of the self-avoiding loop such that a straight line on the bonds of the dual lattice cuts the bonds of the polygon at most twice. The generating function for the number of convex polygons was first derived by Delest and Viennot in 1984.* Their derivation is extremely complicated. A much simpler derivation was found by Lin and Chang in 1988.3 Another simple proof was given independently by Kim.4 Recently Enting and Guttmann5 proposed two empirical formulae of the generating functions for the first and second area-weighted moments of convex polygons on the square lattice : p, 6) = 2x” fkpnk n = x4 (1 _ 12~2 + 50~4 - 76x6 + 42x8 - 48x” + 32x” )/(I - 4x’)“’ + 4x8/(1 - 4x2 )S’2 (1) P?(x) = Cx” f [k(k - 1)/21pnk I? = x6 [R(X)/(l - 4x2 )6 + S(x)/(l - 4x* )9’* I 399 (2) 400 where = 2 + 5x2 - 2 2 4 x4 + 1306x6 - 3352x’ + 4536x” - 3424~‘~ R S = - 2 9 x2 + + 1664~‘~ - 512~‘~ 1 7 2 x4 - 356x6 +312x6 - 120x” is the number of convex polygons with n steps and area k. The first generating function (1) has been derived recently by Lin6 and the result agrees with their conjecture. The purpose of this paper is to derive the second generating function (2). Hereafter we shall refer to Lin’s paper as I. We shall follow the procedure and notations of I as close as and P, k possible. 11. THE FlRST SPEClAL CASE Consider first the special case where the width at the top row equals the width of the bounding rectangle. We define (3) G ”( x) = Fk [k(k - 1)/2lg, ix” = I: G;l, m where gn k is the number of polygons with steps n and area k, and Gi is the generating function corresponding to all polygons whose width at the top row is m. We have G;‘(x) = x6(1 +3x2 +6x4 +10x6 + . . .) = x6/(1 :x2)3 . (4) The polygons whose top width is m+l consist of two types of polygons (see Fig. 2 of I). The first type corresponds to adding one unit square to the right side of all polygons whose top width is m, while the second type corresponds to adding one rectangle with area m+l on top of other polygons. Therefore we have G”m+l = x'(G; +G,J+ ??x~('~+~-'~)[G;; +G;(w~+l)+G~(m+l)~/2] n= 1 (5) which follows from the identities (k+l)k/2 = k(k- 1)/2+k (k + m + 1 )(k + ml/‘2 = k(k - 1)/2 + (m + 1 )k + (m + 1)42 . When m = 1, we have G; = x2(G','+G',)+x2(G;+2G;+G2)+x4(G','+2G;+G,) L-. (6) K.Y.LIN 401 and therefore G;’ = x6(1 +8x2 + 5 x4 ) / ( 1 -x2)4 . (7) We rewrite (5) in the form G;+l _ x2 GII, _ x G; x2(m+2-‘0 = R(~) n = @z+~)GL+~ -mx2Gh -(m+2)(m+1)G,+1/2+(m+l)mx2G,/2 . (8) Consequently we have R(m+l)-x2&Z(m) = ( 1 -x’)G~+~ -~x~GII,+~ +x4Gi, = (m + 2)Gk+2 - 2x2 (m + l)Gh+l + mx4 Gk - (m + 3)(m + 2)G,+, /2 + (m + 2)(m + 1)x2 G,+l -(m + l)mx4G,/2 = (mx2 + 2)Gk+, - 2x2 Gk+r + [m(m - 1)x2 /2 - 31 Gm+2 +2x2 G,+l . (9) The general solution of the recursion relation (9) is G; = [akm(m - l)(m - 2)(m - 3)/24 + b:m(m - I)(m - 2)/6 +clm(m - 1)/2 +dlm +el,J.zT +ct (10) where z, = x2 /( 1 + x) and ct denotes conjugate terms obtained from the others by the exchange of x with -x. Substituting (10) into (9), we get an identity for all m: a’+m(m- l)[(l -x)(2m-1)-2(m-2)]/6+b:m[(l -x)m-m+ll +cl,[(l -x)(2m+l)-2ml - 2 x 4 = fjm3 +f,m” +flm+f where f3 = -xal/3 = -x5 /S(l +x>’ (11) THE SECOND AREA-WEIGHTED MOMENT OF CONVEX POLYGONS 402 f2 = (1 +x)aI,/2-xb; = 7 x4 / 8 ( 1 +x)~ fi = -(3 + x&;/6 + bl, - 2xcl, = -x3 (11 - 3x + 2x2 )/S(l + x)’ f = (1 -x)c; - 2xdI, = x2 (2 - x + 3x2 )/4(1 + x)2 and the solution is al, = 3x4 /8( 1 + x)’ bI, = -(ll - 3 x ) x3 / 1 6 ( 1 +x)’ 2 2 cI, = (11 -6x+3x ) x /32(1 +x)’ d; = -x(5 + 9x + 1 5x2 + 3x3 )/64(1 +x)’ (12) . . The coefficient e’+ is determined from Gyz._ - G;’ = (e: + d:)(z+z_ - 2:) - [(CL + di)z: + ctl (13) and we get el, = 3x/32 . (14) Summing over m, we get G” = =m Gil = a:z4,/(1 - Z,)’ +bkZ:/(l - + = d;z+/(l -z+)’ + Z+)4 +ClZ:/(l -Z+13 ++/tl -Z+> + Cf 2x6(1 -x2)2(1 -4x2 +7x4 - 6x6 + 3x8 - 2x” )/( 1 - 3x2 + x4 )’ = x6(2+ 18x2 + 1 1 2 x4 +582x6 +. . .> (15) K. Y. LIN 403 111. SECOND SPEClAL CASE Consider next the special case where the top right-hand corner of the bounding rectangle is also a corner of the polygon (see fig. 3 of I). We define H” = ,ck [k(k - 1)/2]h, kx” = CH; ( x ) m (16) where ; IH;+n+l $- HA+,+Jm + 1) HI+1 = x2 (HA +Hk ) + x2n=O + *mw (m+l)d21 + G,(m + l)m/21 +n;,x 2(m+2-n)[G; + G;(m + 1) (17) . We rewrite (17) in the form S(m) = H;+1 - x2H; - x2 3, *;+,+I = (m + l)(Hh+l - Gk+l ) - mx2 (Hh - Gk ) + (1 - x2 )GL+I - x2 G; - (H,,, - Gm+l )(m + 2)(m + 1)/2 +x2(*, - G, >(m + l)m/2 (18) . The recursion relation for Hi is s(m + 1) - S(m) = H;+2 - H;+1 + x2 *; = (1 - x2 )G”+2 - G;+l + x2 G; + Cm + 2)(Hm+2 - G;+2) - (m + 1 )(I + x2 )(H;+1 - G;+l ) + mc2 W:, - G; ) - wn+2 - %+2 )(m + 3)(m + 2)/2 + (*,+I - G,+1 )(I +x2)(m +2)(m + 1)/2 - (H, - Gm )x2 (m + l)m/2 i_ ._ . (19) THE SECOND AREA-WEIGHTED MOMENT OF CONVEX POLYGONS 404 The solution of (19) is % = z; [A;m(m - l)(m - 2)(m - 3)/24 + B;m(m - l)(m - 2)/6 + q?r(m - 1)/2 +Q?I +q +ct + w”’ [A’m(m - 1 )(m -2)(m - 3)/24 + B’m(m - 1 )(m - 2)/6 + C’m(m - I)/2 + D’m + E’] , (20) Substituting (20) into (19), we get an identity for arbitrary m: zycf4m4 +f3m3 +f2m2 +fim +f)+ct+wm+l(g3m3 +g2m2 +g,m + g ) where f4 = x3(1 +2x)A;/24(1 +x)’ = a:x3(1 +x-x2)/24(1 +x) . f3 = x3(1 + 2x)B;/6(1 +x)’ - (2 +5x + 2x2)x2A;/12(1 +x)~ = b;x3(1 + x - x2 ) / 6 ( 1 +x)-u;x2(2+3x-x2 +x3)/12(1 +x) + (A, -a+)x3(1 +x -x2)/2(1 +x)2 f2 = x3(1 +2x)C+/2(1 +x)2 -x2(1 +2x)Iq/2(1 +x)2 + x2 (12+23x + 10x2)A;/24(1 +x)~ = c[ex3 (1 +x - x2 )/2(1 +x) - blx2(1 +x -x2 +x3)/2(1 +x) +a;x2(12+11x-x2 + x3 ) / 2 4 ( 1 +x)+(B+ -b+)x3(1 +x-x2)/(1 +x)z +(A+-a+)~‘(-3-4x+2x2 -2~~)/2(1+x)~ +x”(l+~-~2)/ 4( 1 + 2x)( 1 + x)2 fl = x3(1 +2x)D1,/(1 +x)2 -x2(2-x)(1 +2x)Cl/2(1 +x)2 +x2(3+5x+4x2)B:,/6(1 +x)’ -A;x2(4+7x+4x2)/12(l +x)2 = d;x3(1 +x-x2)/(1 +x)+c;x2(-2-x+3x2 -3x3)/2(1+x) +b;x2(3+2x+2x2 - 2 x3 ) / 6 ( 1 +x)-a;x2(4+3x+x2 -x3)/12(1 +x) (21) K. Y. LIN 405 +(C+ -c+)x’(l +x-x*)/(1+x)* +(B+ -b+)2X2(-1 -x+x* -x’)/ (1 +x)2 +(A+ -a+)x2(-1 -x+7x2 -x3)/2(1 +x)* -x7(2+x-3x2 f +3x3 )/4(1 +x)*(1 +2x) = E;x3 (1 + 2x)/( 1 + x)* - D;x* (1 - x>( 1 + 2x)/(1 + x)* + C;x4 /(l + x>* = eix3 (1 + x - x2 )/(l + x) - dlX* (1 - 2X2 + 2X3 )/( 1 + X) + CiX4 (1 - X)/( 1 + X) +(c+ -c+)x’(-I -x+x* -x3)/(1 +x)2 +(B+ -b+)x2(-1 -x+3x2 -X3)/ ( 1 +x)2 +(A+ -a+)2x4/(l +x)* - x7 (1 + x - 2x2 + x3 )/2(1 + 2x)(1 + x)2 A’(2w -1)/6 = -x*0/2 g3 = g2 = B’( 2w - 1)/2 + A ’ ( 1 - w)/2 = -x*E +D(5w - 2 - 2x2 - x*/w)/2 -x8/(1 - 4x2) g1 = C’(2w - 1) + B’/2 + A’(w - 2)/6 = -x*F+E(4w-2-2x2)+D(8w-l-x2)/2+x6[5w-3(1+x*) +x*/wj/(l -4x2) g = D’(2w - l)+C’w = 2wD+E(4w-l-x2)+F(2w-l-x2)+x6(6w-2-2x2)/(1-4x2), with A+ - a + = x6/4(1 +x)(1 +2x) B, - b, = x5 (-5 - 9x + 2x2 + 4x3 )/8( 1 + x)(1 + 2x)* C+ -c+ = xs /8( 1 + 2x)’ From (22) we get 2 A: = 3x4(1 + x - x ) / 8 ( 1 +x)(1 + 2 x ) (22) THESECONDAREA-WEIGHTEDMOMENTOFCONVEXPOLYGONS 406 q = -x3 (11 + 30x + 2x2 - 3 1x3 + 6x4 + 1 2x5 ): 16( 1 + x)(1 + 2~)~ c:, = x2 (11 + 49x + 50x2 - 41x3 - 33x4 + 100x’ + 60x6 - 48x’ - 32x8 )/ 32(1 +x)(1 +2x)3 0; = x(1 +x)(-5 - 24x - 42x2 - 35x3 + 8x4 + 44x5 - 32x7)/64(1 + 2x1~ El = x(1 +x)(6 + 42x + 105x2 + 11 1x3 + 4x4 - 108x5 - 64x6 + 64x’ + 64x8 )/ 64( 1 + 2~)~ A’ = -6x’O/(l - 4~‘)~ B’ = -9x’O /(l - 4x2 )2 - x8 (8 - 27x2 )/(l - 4x2 )5’2 C’ = x8 (-6 + 23x2 )/( 1 - 4x2 )5’2 +x6 (-2 + 1 3x2 - 25x4 + 1 Ox6 )/( 1 - 4x2 )3 D’ = x6 (2 - 9x2 + 6x4 - 2 x6 ) / 2 ( 1 - 4~~)~ +x8(-l +6x2 - 18x4)/ 2( 1 - 4x2 )“2 (23) Finally we calculate E’. We have H’I = [(D; + E;)z+ + ct] + (D’ + E’)w H;’ = [(C+ + 20; + E;)z: + ct] + (C’ + 20’ + E’)w2 (24) It follows from (17) that H;’ = x2 (HI’ +H;) +x2 n;,(H;+2 + 2H;+2 + H,,+2 )+x"(G','+2G;+G,) Z = x2 i, (H;+, +HJI+l ) and therefore we have H;’ -HI’ = x4 (GI’ + 2G; + G, ) +x2 zo(H;l+2 + H,,+2) = x4(G;‘+2G; +G,)+_?(H’+H-H; -H,) = x6 (1 - 1 lx2 + 16x4)/2(1 - 4x2 )3,2 +.a?(3 - 3x2 + x4)/(l - x2 ~3 (25) i. - 408 THLSECONDAREA-WEIGHTEDMOMENTOFCONVEXPOLYGONS 1V. GENERAL CASE A convex polygon can be divided into two (top and bottom) polygons as shown in fig. 5 of I. The area K of the polygon is the sum of K[ (the area of the top polygon) and K~ (the area-of the bottom polygon) and we have the identity k(k - 1)/2 = k,(k, - 1)/2 + k,k, + k, (kb - I)/2 . (30) Following the same procedure of I, we have = G” + 2zz2’GL h,,, + GI, hl, + G, h; ) +mf3(G;gm + GA p; + G,g; ) (31) where gi, = m-2 2n (m-n- 1)Gfi . The calculation of P2 is very complicated. We shall leave the details in the Appendix. The final result is pz (x) = x6 (R/A” + S/A9’2 ) = x6 (2 + 24x2 + 21 8x4 + . . . ) (32) where A = 1 - 4x2, R and S are defined by (2). Our result agrees with the conjecture of Enting and Guttmann.’ ACKNOWLEDGMENT I thank professor Guttmann for sending their preprint prior to publication and the National Science Council for financial support. K. Y.LIN 409 APPENDlX The generating function P2 is derived in this appendix. It was shown in I that gtrl = -1 + [(I +xp +(l -xp l/2 g;, = - 0 ; x(1 + xpm /4 - m(l - x2 )/8( 1 (Al) +xy -( 1 -x*)/8x(1 +xy + ct 042) h?l = -1x/2(1 + 2x)(1 +x)m-j +ct] -x4(1 +A1’2)A-1(w/x2)m hl, = [ 0 +Y1 ; +m+ a+ +r+l(l +xY fct (A3) a +mp (w/x’ 1” (A4) where . (y = -x6@-’ + A-3’2) 0 = _-2x8,-2 Y = x4 ( 1 + 4x4 )/2A2 + x4 /2A3’* &+ = x2(1 +x)2/4(1 +2x) 0, = -x(1 +x)‘(l + 3 x + 2 x2 - 4 x3 ) / 8 ( 1 +2x)’ y+ = x3(1 +x)‘(l -2x)/4(1 +2x)* . We have g; = m-2 z x-*/‘(m - n - n=l I)G; = 4:f4 + bkf3 + c>f2 + where It follows from the identity k;. Ykf, = m-2 (m -n - I)[(1 ,,.$ +v)/(l +x)J” d:fl + elf,, + ct 645) THE SECOND AREA-WEIGHTED MOMENT OF CONVEX POLYGONS 410 = m(l +y)/(x -y) + [(l +v>2 - 2(1 +u)(l +x) + (1 +JJ)m(l +X)2-m l/(x -v)2 646) that fO = [-l-2x+mx+(i +X)2-ml/X2 fk = m( 1 + x)/xk+l - (k + 1 )(l + x>2 /T8+2 + (1 + X)~-~ ii 0m i=O i (k + 1 - i)/xk+2-i , k>O. (A7) Substituting (A7) into (A5), we get 3x2/8(1 +x)“’ + m 0 +2 x(1 +3x)/16(1 +x)” 3/32( 1 + x)“+~ + 3m(l - x2 )/64x(1 + x)“‘-l + cf. 648) Similarly we have ,,” = m m~-lx-hh* n=1 649) n where + ctl + A’F4 n (w) + B’F, n(w) + C’F2 n(w) + D’F, n (w) + E’Fo n (w) Fk,, (f) = p;[;j t”+P = ii(:) t”+k-i/(l - t)k+l-i and the last equation follows from the identity It can be shown that 1 In- c II= 1 x-~‘~F~,,,(~) = k. tk-‘(1 - t)r-k-l f,, (t/g > (A101 K. Y. LIN 411 where fr,, (t> .= m-l z n=1 n 0 t” = f(l _t)-‘-1 -t”(l -t)-1 ;: (m ) s=o r - s r [t/(1 - t)1’ , r> 0 (t - tm )/( 1 - t) fO,m = f 1P = t/(1 - t)Z - tm+l /(l - tj2 - mtm /(l - t) f 2P = t2 /(l - t)3 - tm+2 /( 1 - t)3 - mtm+’ /(l - t>2 - (;)P /(l -t) . After some algebra, we find h; = [(l +xym IS4 m pi + i=o 0i ctl + (w/x’ )” i$o ; 0 4; (Al 1) where . P4 = uA: = -3x3(1 +x)/8(1 +2x) P3 = u(B; +v,A;) = x2(1 +x)(5 +7x -6x2 - 12x )/16(1 +2x)2 P2 = u(C; +v,B; +v,A;) 3 = ex(l + ,y)( 1 + 4x + 7x2 + 4x4 + 32x5 + 32x6 )/32(1 + 2~)~ Pl = u(D; + v, C+ +v2B: + v3A;) = (1 +x)(3 + 21x + 57x2 + 79x3 + 12x4 - 76x5 - 32x6 + 32x7 )/64( 1 + 2x1~ PO = U(E; + v,D’, + v2 Cl + v3B; + veA)+) = (1 + x ) ( 3 + 2 1 x + 5 1 x 2 +45x3 - 54x4 - 178x* - 72x6 + 1 84x7 + 1 60x8) /64x( 1 + 2~)~ U = VI = -x2/[(1 -2+)(x2 -z+)J = -(I +x)2/x(l +x-,x2) z+/(l - z+) +z+/(x2 - z+) = (1 +x -x2 +x3)/x(1 +x -x2) THE SECOND AREA-WEIGHTED MOMENT OF CONVEX POLYGONS 412 “rl = z”, &(l - z+)-j(x2 - z+p = [z+/(l -2+)(x2 -z+)l”[(l -z+)“+l -(x2 -z+)““l/(l -x2) = [(l +x -xy+a -x3@‘1)]/(1 +x)(1 -x’)x”(l +x-x2y q4 = A’lw = -3x8(1 +A”‘)/A’ q3 = (B’ + A’v;)/w = -x6/A2 + ( - 1 + 6x4 )x~/A”~ q2 = (C’ + B’v; + A’v;)/w = x6(1 -2x2 - 2~~)/2A”~ +x6(1 - 10x2 + 14x4)/2A3 41 = (D’ +C’v;+B’v;+A’v;)/w . = 2x8(1 - 2x2)/A3 -x*(1 -2x2 +~x~)/A”~ 40 = (E’ + D’v; + C’v; + Bb,’ + A’v:)/w = -x4 (7 - 42x2 + 88x4 - 76x6 + 28~~)/2A”~ - x4 (7 - 42x2 + 94x4 - 104x6 + 64x8 )/2A4 v; = [(I _ w)“+l _ (x2 _ w)“+l ]/(_x’)“(l -x.2) 1,; = -1 _A1’2/x2 11; = (2 - 7x2 + 2x4 + 3x2 A”’ )/2x4 1); = -(2 - 7x2 +x4 )/x4 - (1 - 3x2 + 2x4 )A1’2 /x6 1,; = [ 2 - 1 3x2 + 27x4 - 23x6 + 2-P + (5x2 - 1 5x4 + 5x6 )A”’ ]/2x8 2~2 = 1 _ 2x2 _ A”’ 2w3 = 1 _ 3X2 _ (1 _x’)A’,‘z 2w4 = 1 -. 4x2 + zx4 _~ (1 _ 2X2 )A”2 (El + c)” + ct) + k“ + q,, + H” = 0 i-- K. Y. LIN 413 p. + ct = x4 (7 - 51x2 + 1 37x4 - 1 68x6 + 80x8 )/A” p, + ct = (3 - 30x2 + 19x4 + 280x6 - 752x8 + 384xl”)/32A3 p2 +ct = x2 (1 +7x2 - 8x4 - 48x6 + 128x8)/16A3 p3 + ct = x2 (5 - 27x2 + 64x4 - 48x6 )/8A2 p,+ct = 3x4/4A . Substituting hh into (31), we obtain 2;G mc2 nl h" m (Al21 =;S /I=0 'I where (i = 0, . . . , 4) si = x2 x [x/(1 +xp ; p,+ct m 0 . s,, = 'i+lO x2 2 [x2 /(l - x2 m )I” 7 0 pi + cl =x2 T2 [W/(1 +x)Jrn mi qi+ct m 0 * It follows from the identity tm = t’/(l -t) k = O = t2 (2 - t)/(l - t)2 k=l = tk/(l - ty+* k> 1 (Al3) that so = p,x6/(l +x)*(1 +2x)+ct = x6 (-6 + 87x2 - 21 5x4 + 358-P - 2456x’ + 6304x” - 601 6xL2 > /16(1 -x2 )/A5 s, = p,s6(2+4x+x2)/(1 (Al4) +x)*(1 +2x)* +ct _ THESECONDAREA-WEIGHTEDMOMENTOI'CONVEXPOLYGONS 414 = x6 (6 - 93x2 + 450x4 - 2767x6 + 1 1204x8 - 20208~‘~ + 15808~‘~ - 512x14)/32(1 --‘)A’ (,A1 5) s2 = p2 x” (1 + x)2 /( 1 + 2x)3 + ct = x8 (5 - 30x2 + 2 8 9 x4 - I 320x6 + 3296x’ - 4864x” + 4352~‘~ - 2048~‘~ )/l 6A6 (Al6) s3 = p3xy1 +x)2/(1 +2x)4 +ct = x’O(5 + 66x2 - 5 1 9x4 + 1 608x6 - 2592x8 + 2 1 76x1’ - 768~‘~ )/8A6 (Al 7) s4 = p4xy1 +x)2/(1 +2x)5 +ct . = 3~‘~ (9 + 1 5x2 - 108x4 + 144x” - 64x* )/4A” ( ‘4 18) ss = @o +&)x6/(1 -x2)(1 -2x2) = x10(7 - 51x2 + 1 3 7 x4 - 168x6 +80x8)/(1 -x2)(1 - 2x2)A4 (A19) s, = (PI + &)X6 (2 - 3x2 )/( 1 - x2 )(l - 2x2 )2 = x6 (2 - 3x2 )(3 - 30x2 + 19x4 + 280x6 - 752x8 + 384x” ) /32( 1 - x2 )( 1 - 2x2 )2 A3 6420) s, = x6(1 -x2)(p2 +ct)/(l - 2x2j3 = x8(1 -x2)(1 +7x2 - 8x4 - 48x6 + 1 28x8 )/16( 1 - 2x2 )3 A3 (A21) s, = @I3 + ct)x8 (1 - x2 )/(l - 2x2 )” = ~‘~(1 -x2)(5 -27x2 +64x4 - 48x6 )/8( 1 - 2x2 )” A2 (A22) s, = (p4 +ct)xlO(l -x2 )/(I - 2x2 )* = 3.~‘~ (1 - x2 )/4( 1 - 2x2 )‘A S,, = x8 (14 - 78x2 + 14.5.~~ - 1 02x6 + 38.x’ )/A” (1 - x2 ) (A231 K. Y. LIN -x8(14 415 - 92x2 + 217x4 - 222x6 + 1 18x8 - 56x1’)/A9’* (1 -x2) (~24) S,, = x8 (3 - 1 3x2 + 1 6x4 - 2x6)/A4 - xl0 (6 - 35x2 + 58x4 - 26x6 ) /(I - x2)A4 - x8 (3 - 19x2 + 36x4 - 22x ” )/A9” + xl0 (6 - 23x2 + 26x4 - 2x6 )/( 1 - x2 )A”’ s,, = xa (6 _ 29x* + 46x4 - 22x6)/04 - x8 (A25) (6 - 41x2 + 90x4 - 70x6 + 8x8) /ASi2 (A26) S,, = x6 (2 - 10x* + 1 8x4 - 6x6)/A4 - x6 (2 - 14x2 + 34x4 - 30x6 )‘/A9” (~27) S14 = 6x8 (4 - 19x2 + 26x4 - 12x6)/A4 - 6x8 (4 - 27x2 + 56x4 - 42x6 + 8x8 )/A”’ . (A28) where we used the following equations = [2 - 5x2 - (2 - x2 )A”’ ] /2(1 - x2 )A1’2 -[l -2x2 - 2x4 - A*‘? ] /2x(1 - x2 )A*” Z,‘” - l)[w/(l +x)1” = w’/(l +x - w)2 = [l -3x2 - (1 -x’)A”~ ](I - 2x)/2x2A mg*b(m - 1)/2J [w/(1 +x)Jm = w2(1 +x)/(1 +x - Iv)3 = [2 - 9x2 + 8x4 - (2 - 5x2 + 2x4 )A”’ ] /2x2 A312 + [ - 1 +5x2 - 7x4 +4x6 +(l -3x2 +3x4yA1”1 c m=2 /2x3 A3’* in 0 3 [w/(1 +x)1” = w3(1 +x)/(1 + x - w)4 = (1 _3x+4x3)[1 _5x2 /2x4 AZ +5x4 -(1-3x2 +x4,A”‘l 416 THE SECOND AREA-WEIGHTED MOMENT OF CONVEX POLYGONS 00 c m=2 m 0 4 [w/(1 +x11” = w4 (1 + x)/(1 + x - w)S = [4 - 31x2 + 79x4 - 79x6 + 28x8 _ (4 - 23~~ + 41x4 - 27x6 + 4x* )A”’ I /2x4 A5’2 + [-1 +4x2 + 8x4 - 44x6 + 42x* - 8x” + (1 - 2x2 -10x4 + 24x6 - 12x’ )A1’2 I /2x5 As’2 (~29) to derive (A24) - (A28). Substituting h,,, and hm ’ into (3 1 ), we get 00 2m m . 6430) where f4 = a; , f3 = b; , f2 = cI, , f, = d: , f. = el, , 2 ; Cl, h;, = 2E[cum(m-1)/2+flm+y][a+m(m-1)/2+ m m=2 + b + m +c+l [w/(1 +x)1” +2X [a+n~(m - 1)/2 + ),I + fi+rn + y, 1 [a+m(m - 1)/2 + b+m + c, 1 [x/( 1 + x)J 2’n + 2C [cr+m(m - 1)/2 + p+m + y+ I [a_m(m - 1)/2 m + b _ m +c - j[x2/(1 -x’)j”’ +ct (A31) where % = -x3 /4(x 5 1) Using the identity b, = x2 (3 k x)/8(1 f x) c, = -(5x)/8 . K. Y. LIN [Am(m - 0 QA ; 1)/2 + Bm + C] [am(m - 1)/2 + bm + CJE +3(uB+bA+2aA) 417 (~32) + [aA +aC+cA +2(aB+ bA+ b&l ‘: 0L + (bB+ b C + c B ) m + CC , we can express (A30) and (A31) in the form (-433) where (i = 0, . . , 4) r.; 47 [x/Cl +xPm+ct ‘i+l5 = ‘i+*Cl =si mx i ‘m= i m . 0[x2/(1 0 [w/Cl , m y ‘i+25 = t.2 -x2>lrn +x)1" +ct 3 r. = -x*(1 +x)*(3+9x+8x2 - 4 x ) / 3 2 ( 1 +2x)* rl = x2 (1 + x)(7 + 21x + 23x2 + 23x3 - 2x4 )/64( 1 + 2x)* r2 = -x3(1 +x)(19 +26x - 23x2 - 18x3 )/32(1 +2x)* r3 = x4 (1 + x)( 1 - 2x)(23 - 9x- 92x2 + 24x3 + 24x4 )/16A* r4 = -9x5 (1 - x - 2x2)/8A 4 so = x2(3 - 19x2 + 3 2 x + 16P)/16A2 SI = -x2 (5 - 1 2x2 + 6x4 - 124x6 - 3x8)/32n(l -x2)* -x2(1 -3x* - 9x4 + 47x6 - 4,u8 >/ 16( 1 - x2 )A* 32 = x4(-39 + 101x* + 2 1 9 x4 + 3 9 x6 )/16(1 -x’)‘A +x4(-l +24x2 - 91x4 + 100x’ )/S( 1 - x2 >A2 s3 = 3x4 ( 1 - 6 x ’ -x4 +30x6 +8x8 )/4(1 --*)A* THE SECOND AREA-\YEIGHTED MOMENT OF COSVEX POLj’GOSS 418 - ~“(1 1+9x2-195x4 49x6) / 8(1-x’)*A s4 = 3x6(-1-2x2+19x4) / ~(I-x*)~A lo = -~~[5--12x*+Sx~i(5-12x~)A~~~] I~ = / 16A’ x5[5+21x+1 lx*-29x3+Ix4+20xs+16x6) + (5+21x+11x2-29x3-60x4-12x5)A1’*] / 32(1-+x)‘A2 l2 = - x6[1 1--6x-21x2+6Ux3-28x4-32x5) + (1 1-6x-21x2+31x3-12x4)A”2] / 16(1+x j2A2 . t3 = x7[(11-13x+9x2+169x3-221x4+6x5+120x6--Gx7) + (11--?3x+9x2i97x3-1Wx4+30xs)A1~2] / S(l-x2)‘A2 f4 = - 3x*[1--&+x2+12&-Qx4 I (1_6x+5~~i_?x~~.r~)A~‘~! ! :(!-x~)~A”*. It follows from (A13) that SlS = ro x4 / (l+x)‘(1+2X) + Cf = - x6(3-10x2+d8x4+32x6) t 16A3 s;6 = rl x4(2+3x+x’) / (l+x)‘(l+2x)‘+ = (A33) cf ~~(1335,~*-1S3~~-33~~+1SQ0x*-336x~~ / 33(1-x’)A4 (A39 s17 = r2 x4(1+x)? I (1+2x)3 + Cl = x8(107-690.~2+1635x4-2076x”+1616x8-576.r’o) s,s = r3 x6(1+x)? / (1+2x)’ + 1 = / 16.I’ (A36) Cf x’0 (23+270x2-25S9x4+6576x6-7~SSx8k036xS-76Sx1@) .S19 = r4 x8(1+x)* / (Ii-2~)~ + cf I 8A6 (A37) K. Y. LIN = 9x’~(9i15x*-10sx4+l??x~~x~) / 4A6 419 (A3S) sa = so x4 / (1-x2)(1-2x2> = x6(3-19x2+32x4+16x6) / 16(1-x2)(1-2x’)A’ (AW 52, = S) x4(2-3x2) I (1-x*)(1-2x*)2 =- x6(10-39x2+4Sx4-266x6+366x8+9x1@) - x~(‘-9.~~-gx~+121x~-1:9x*+12x~q I 32(1-x2)3(1-2x2j2A / 16(1-x’)2(1-2r2)2A2 (A40) sp = s* x4(1-x2) / (1-2x2>3 =x8(-39+101x%219x4+39x6) I 16(1-x2)(1-2x*)3A + xs(-1+24x2-91x4+100x6) / 8(1-2x2)3A2 (A40 su = s3 x6(1-x2) / (r-k2>4 = 3x10(1-6x2-x4+30x6+8x8) - SSJ = = x’“(11+9x2-195x4~9x6) s4 / 4(1-2~~)~A* / 8(1-~*)(1-2x*)~A (~42) x8(1-2) / (1-2x*)5 3x+-1-2x2+19x’) / 4(1-~3(1--2x*)~A (A43) Su =x6(5-13x2+4x4-8x6) I ~(I-x~)A”~ - x6(5-3x2-12x4) / S(l-x2)A2 (A441 Sz = x6(3-26x2+130x4-278x6+399x8+60x’? (A45) / E(~-x~)~A~ - x6(3-14x2+63x4-28x6) / 8(1-~‘)A”~ Sn =x:(42-155x2-71x4+5x6) I 8(1-x2)A3 - x6(42-239x2+177x4+4-48x6+11~*) / 8(1-x2)4”’ Sn = -x5120-183x2+484x4-316x6+184x8 -. L (A46) THE SECOND .4REA-N’EICHTED hlOSlfST OF CONVEX POLYGONS 420 - (30-113~~+2~s~4~6x~+120x*)~~‘~] / 2(1-xQ4 @47) SB = 3x6[2-39x2+16Sx4-240x6+16Sx*-32x10 - (2-35x2+102x4-9Sr6+56xs)A’!2] / 2(1-x2)A4. Substituting g, , g,,2, , g,” into (31), we get +G;g;+G,g;)=C;'+G;-G"+ FSk k=30 w!lere (i=O,...,4) Sj+30 = . *imt3 ~~][X/(liX)lh + Cf Si+35 = vimc3 ~)[x2~(1-X2)1m u4 = (l+~)~u;/2 - 3x(l+x)aJ2 + 3x4/16 = 3xs/4 u3 = (l+x)2f+2 - 3(1+x)(1+3x)aJ8 - 3x(l+x)b+A + xZ(l+3x)/32 =x3(5+3x)/8 112 = (1+x)%;/2 - (Ii-x)%JSx - (l+x)%J3 - x(l+x)c+E + 3x2(1+x)%4 = x2(3-x+x2) / 16 u, = (l+x)‘Q2 - (1+x)(1-x2)bJSx - (I-x?)cJS + 3x(1-x~)(l+x)/12S = -x(3+4x+7x2+2x3) / 64 u. = (lsx)‘e;/2 - (l-x2)cJSx = (I+x)(l+2x+3xzj / 64 v4 = (l-x)%;/2 + 3x(1-x)0+/2 + 3x4/16 + CI = 3x6(l+xz) / 2(1-x2)” ~3 = x’(5+20x2+3x”) / 4(1-x2)l v2 = x2(1+21*2+17x4+x6) / 8(1-x2)2 vi =x2(1+9x2+7x4-x6) / 16(1-~~)~ K. Y. LIN 421 Yg = -(1+5x2) / 32. It follows from the identity k=O = t3(3-21) I (1-Q’ k=l = r3(3-3t+f2) I (1-f)3 k=2 = fk / (l-#+I k>2 (A50 that SK) = ug x6 / (1+x)*(1+2X) + ct = X6(1+2JJcz+15X4+GX6) I 32(14)3A (A511 S3l = 111 xyMr+X*) / (l+X)4(1+2X)z + Cf = ~~(21-26~~-7O~~-251X~+35X~-4X~o) / 16(1-X’)‘A 2 (A52) S32 = U2 X6(3+12X+15X2+6x3+X4) / (1+X)1(1+2r)3 + Cf = x8(9+84.r2-633X4+-6S9X6+900X8+27X’o +4X12) / 8A3(1-X2)” 0453) s33 = u3 x6(1+x)2 / (1+2X>? + Cf = ~‘~ (27-5X’- 72~~+3Sx~) Sg= I lA4 W-I) u4 2(1+x)2 I (1+2.# + Cf 3x”( 1+21x2-40x4+16x6) /2As 6455) = -x6(1+5x’) / 32(1-~~)~(1--2~~) 6456) = s 35 = v&x6 / (1-x2)‘( 1--zx*) ss = Vl x6(3-5x2) I (l-x~)~(1--2X2)* --- THE SECOND AREA-WEIGHTED MOMENT OF COti’VE); POLYGONS 422 = ~*(3+22r~-2~~~-3&.~+5~~) / 16(1-~~)4(1--2x~)~ (A57) sj, = v2 x6(3-9x2+7x4) / (l-x2)2(1-2x2)3 = x~(3+53x~-131x4-3x~+11ox~i7x*4 / S(b-x2)4(1-2r~)~ (A5Q S38 = v3 x6(1-x2) / (1-2x2)4 = x’“(5+20x2+3x4) / 4(1-x~)(1--2r2)4 (A59) s,, = v4 xy1-32) / (1-2x2)5 = 3x’“(l+x?) / 2(1-x2)(1-2x2)5. (AGO) Finally we have S; E Sg + = S24 + SJ~ 3x”(l-3x2) / 2(1-~~)(1-2x~)~A s; =s; i-s*+su+sj, = x’“(5-32~2+57x4-6x6+23x8) / $(L-~x~)~(~-x~).I~ = x8( -17+292r2-1791x4+1919x6-5321x8-365x’o~’~_718.l:‘~+712r’4-~,r’~) / S(1-~‘)4(1--2r~)~A~ S; = S; + S6 + S2, + S36 = x6( -?+3x2+37Ox4-2222x6+3~~x8+3O79x1o-S382x’2+S96x”-22~x~6) / 16A3(1-_x2j4(1-2x2) = x6( -3-~9x2+~~23~4-9~S7x6+2244Ox8-9362~'o-212OSx'2-2272x'-+~S4x'6) s; = S; + SJ1 + Sj2 + G; =x6( 29-2OSx2+255x4+15~.~6-5316x8i33SSx1o+992x’2-192x’4) --__ -~ ._ / 3’(1-_~~)~A~ / 33(1-x’j4A4 L.’ 423 I;. Y. LIY S; f S, + S26 + SjO+ G; = x6( 37-367x2t13SOx”-1S54x6-36Sxs-96x*? - x6(3-11x2t63x4-232) / 16(1-x2)A” / S(1-s~~)~~ t ,~~(~-13X~+3~4k0x6-10x8-~?x1~ I A”’ p2=c; +c; + ?s, k=o = . s, + s2 + s, t + Sls + s4 + sn + s13 + s14 SIT + Sl* + Sly + Sjj + SX = x 6(R /A6 + S /AgJ2) Lvherz R and S are defined by (2). -- 6461) r 424 THESECONDAREA-WEIGHTEDMOMENTOFCONVEXPOLYGONS REFERENCES 1. P. G. de Gennes, Scaling Concepts in Polymer Physics (Cornell Univ, N. Y., 1979). 2. M. P. Delest and G. Viennot, Theo. Comp. Sci., 34, 169 (1984). 3. K. Y. Lin and S. J. Chang, J. Phys. A 21, 2635 (1988). 4. D. Kim, Dis. Math. 70, 47 (1988). 5. I. G. Enting and A. J. Guttmann, J. Phys. A 22,2639 (1989). 6. K. Y. Lin, Chin. J. Phys. 27, 235 (1989).
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