First, find the values of a, b, and c for the parabola. y = ax2 + bx + c y = x2 + 12x + 20 a = 1 b = 12 c = 20 If a > 0 the parabola opens up, if a < 0, the parabola opens down. Since 1 > 0, the parabola opens up. x = (‐12 / 2*1) x = ‐6 y = (‐6)2 + 12(‐6) + 20 y = 36 – 72 + 20 y = ‐16 So the vertex is (‐6, ‐16) Find the x‐intercepts. 0 = x2 + 12x + 20 0 = (x + 10) (x + 2) x + 10 = 0 x + 2 = 0 x = ‐10 x = ‐2 The x‐intercepts are at ‐10 and ‐2 (as ordered pairs we would write these as (‐10, 0) and (‐2, 0) but it does not ask us to write them as ordered pairs in our answer) Find the y‐intercept. y = (0)2 + 12(0) + 20 y = 20 As an ordered pair this would be written as (0, 20) Choose the parabola tool under the graph. Maximize the graph to enlarge it. Choose the parabola tool on the right. First, plot the vertex (‐6, ‐16) notice in the upper right corner it shows you exactly where you are on the graph so you know before you click that you’re in the right place. After you get the vertex plotted, you want to plot the x‐intercepts. Just based on where your cursor will be it is asking you to plot the x‐intercept that is on the right which is (‐2, 0) Once you get that plotted you notice the parabola is already exactly where it should be. The other x‐intercept, at (‐10, 0) is already in the right place. Now look at the y‐intercept, which should be at (0, 20). It is also already in the right place. So “save” the parabola and you are done!