Evaluate each expression. PRACTICE (1) log 16 _____ (2) log 1 _____ (3) log (4) log (5) log 3 _____ (6) log (8) log (9) log _____ (12) log 2 _____ 10 _____ (7) log (10) log PRACTICE _____ / / (11) log 243 _____ _____ 81 _____ _____ / 8 _____ Use the log button on your calculator to evaluate each expression. (13) log 100 ______ (14) log 10 ______ (15) log 10,000 ______ (16) log 1 ______ (17) log 0.1 ______ (18) log 0.001 ______ (19) Note your answers to #13β18 What base does the log button appear to be using? ________ HOW DO YOU KNOW? PRACTICE (20) According to the calculator, log 6 β 0.778. Why is the answer smaller than 1 but greater than zero? ______________________________________ PRACTICE (21) If log 29 = π₯, then x must be between ____ and ____. WHY? PRACTICE (22) If log 625 = π₯, then x must be between ____ and ____. WHY? PRACTICE (23) If log WHY? PRACTICE Consider the following information provided. Determine the value of the missing base. 0.5 = π₯, then x must be between ____ and ____. (24) log ____ 16 = 4 log ____ = β3 log ____(2 β 2 ) = 13 BASE: _______ (25) log ____ 5 = 1/2 log ____ log ____ = β2 BASE: _______ (26) log ____ 4096 = 4 log ____ 4 = 2/3 log ____ 2 =6 BASE: _______ =1 PRACTICE Dr. Tuppersupper has invented his own calculator. It has all of the same digits 0-9, but the other buttons function differently. For instance, on his calculator, log 10 does not equal 1, as it does on a normal calculator. Instead, on his calculator, log 10 = 0.926628408. Furthermore, log 100 = 1.853256816 and log 1000 = 2.779885224. (27) What base is his calculator using? ______ (28) In the space at right, prove your answer to #27. PROOF: REVIEW Find the x-intercept(s) of each function. (30) 5π₯ β 3π¦ = β20 (29) π¦ = 6π₯ β 24 x=____ x=____ ____ x=____ ____ (33) 2π¦ β 4π₯ = β20 (32) π¦ = 5π₯ + 5π₯ β 100 (34) π¦ = π₯ β 2π₯ β 3 x=____ x=____ ____ REVIEW (31) π¦ = π₯ + 2π₯ β 3 x=____ ____ Write a system of inequalities for each graph below. (35) (36) y (37) y x x (38) y y x x __________ __________ __________ __________ __________ __________ __________ __________ REVIEW Factor each expression. (39) 9π₯ β 1 ( )( (40) 3π₯ + 11π₯ β 4 ) (42) 9π₯ β 6π₯ + 1 ( )( REVIEW ( )( (41) 3π₯ + 13π₯ + 4 ) ( (43) 3π₯ β 13π₯ + 4 ) ( )( )( ) (44) 3π₯ β 11π₯ β 4 ) ( )( ) Let π(π₯) = 3π₯ β 2, π(π₯) = π₯, β(π₯) = 4π₯ β 2π₯ + 6, π(π₯) = 8 β 2π₯. (45) π(π(2)) ______ (49) π(β(π₯)) _______________ (52) π(π(π₯)) _______________ (46) β(π(β4)) ______ (47) β(π(2)) ______ (50) β(π(π₯)) _______________ (53) π(π(π₯)) _______________ (48) π(β(β8)) ______ (51) π(π(π₯)) _______________ (54) π(π(π₯)) _______________
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