page 1
Measurement – AP Book 6.2
AP Book ME6-8
page 266
1.
2.
3.
4.
a)
5 fingers: 50 mm
b)
7 fingers: 70 mm
a)
38 mm
b)
47 mm
a)
Teacher to check.
b)
Teacher to check.
a)
i) Same length
ii) Same length
b)
5.
12. a)
b)
910 mm
c)
45 cm
d)
2 cm
e)
6 200 mm
Diagonal: 5.2 cm, 52 mm
Sides: 5 cm, 1.5 cm
7.
10
8.
10
9.
mm
cm
130
13
320
32
mm
cm
80
8
180
18
mm
cm
2 130
213
1 700
170
mm
cm
90
9
5 670
567
420
42
d) 70 mm
cm
dm
80
8
6 200
18. No, Rebecca is incorrect.
When 3 cm is converted
in millimetres it becomes
30 mm. 30 mm is greater
than 7 mm.
19. a) 4 cm + 4 cm
m
mm
5
5 000
17 000
620
cm
mm
300
30
4
40
cm
dm
121
1 210
530
53
dm
cm
10
1
32
320
95
5
50
5.
Teacher to check.
a)
4 m 23 cm
5 m 14 cm
c)
6 m 27 cm
10. 10
d)
6 m 73 cm
d) 7 cm + 7 cm + 4 cm +
4 cm + 4 cm
11. 100
e)
3 m 81 cm
f)
2 m 3 cm
e) 7 cm + 7 cm + 7 cm +
4 cm
AP Book ME6-10
page 270
6.
a)
283 cm
b)
365 cm
1.
Answers will vary.
a) 7 cm – 4 cm
c)
485 cm
2.
About 28 m
b) 4 cm + 4 cm – 7 cm
(8 – 7)
d)
947 cm
3.
Teacher to check.
e)
704 cm
4.
Teacher to check.
f)
640 cm
5.
Answers will vary.
a)
546 cm
= 5 m 46 cm
= 5.46 m
b)
2 m 17 cm
= 2.17 m
c)
7 m 83 cm
= 7.83 m
d)
6 m 8 cm
= 6.08 m
e)
72 cm = 0.72 m
f)
7 cm = 0.07 m
c)
7 cm + 7 cm – 4 cm +
4 cm + 4 cm (14 –
12)
d) 7 cm + 7 cm + 7 cm –
4 cm + 4 cm + 4 cm +
4 cm (21 – 16)
e) 7 cm + 7 cm + 7 cm –
4 cm (21 – 4)
d)
43
e)
46 cm
f)
6 cm
13 cm
7 000
Teacher to check.
7 cm + 7cm + 4 cm +
4 cm
f)
c)
70
c)
8
180 mm
800
Teacher to check.
320
b)
cm
8
9.
c)
40 mm
m
8.
b)
11. a)
1 000
b) 7 cm + 4 cm
BONUS:
58 cm
3.
b)
20. Possible solutions:
Yes.
Teacher to check.
AP Book ME6-9
page 269
Leg – More
Eraser – Less
Pencil – Answers will
vary.
Door - More
7.
6.
0
1
B E
A
C
D
7.
A kilometre is about
10 football fields long.
8.
Answers will vary.
AP Book ME6-11
page 271
1.
1.
100
17
950
7.
2.
4.
c) 8 cm
5
g)
6.
17. Teacher to check.
10. Divide by 10.
a)
10
31
16. Teacher to check.
60 mm
5.
310
Estimates will vary –
teacher to check.
c)
10
12
15. Teacher to check.
15 mm
4.
6 m, 60 dm, 600 dm,
6 000 mm.
120
72 cm
14. Teacher to check.
b)
3.
1
10
13. Teacher to check lines:
b) 30 mm
i) 30mm
38 mm
10 cm
dm
ii) 20mm
a)
2.
cm
f)
Actual Lengths:
6.
70 mm
Answers listed as
columns:
8.
3 m, 30 dm, 300 cm,
3 000 mm
100 cents = 1 dollar
and 100 cm = 1 m
9.
Yes, Michelle is correct.
She multiplies 6 m by
100 in order to convert
the measure to cm
(since there are 100 cm
in a metre).
4 m, 40 dm, 400 cm,
4 000 mm
5 m, 50 dm, 500 cm,
5 000 mm
Answer Key for AP Book 6.2
page 2
Measurement – AP Book 6.2 (continued)
AP Book ME6-12
page 272
1.
a)
iii)
100 mm = 10 cm
= 1 dm
f)
i)
1 000 times
smaller
ii)
1 000 times
more
iii)
Multiply by
1 000
Largest = dm
Smallest = mm
2.
3.
b)
smaller
c)
more
a)
10 mm
b)
10 cm
c)
100 mm
d)
10 dm
e)
100 cm
f)
1 000 mm
a)
i)
10 times
smaller
ii)
10 times
more
iii)
Multiply by
10
i)
10 times
smaller
ii)
10 times
more
iii)
Multiply by
10
g)
i)
ii)
iii)
10 times
smaller
10 times
more
h)
d)
i)
10 times
smaller
ii)
10 times
more
iii)
Multiply by
10
7.53 cm
= 75.3 mm
e)
i)
ii)
10 times
larger
10 times
fewer
i)
1 000 times
smaller
ii)
1 000 times
more
iii)
Multiply by
1 000
i)
ii)
iii)
a)
m = metre
→ width of a
swimming pool
km = kilometre
→ distance of a
marathon
b)
4.
mm = millimetre
→ thickness
of a nail
2.
40 dm
b)
130 mm
c)
200 mm
5.
45¢
6.
Since the total weight of
emily’s book is 3.703 kg
and is less than her
maximum weight of 4
kg, she can carry all her
books in her backpack.
7.
8.
9.
3.
4.
The perimeter is 244 cm
(2.44 m), and is greater
than 2.4 m.
Both relations are
1 000 times larger units
(1 kg = 1000 g;
1 km = 1000 m).
Both realtions are 1 000
times smller in units
( 1 mg = 0.001 g;
1 mm = 0.001 m).
5.
a)
m
b)
dm
c)
m
a)
cm
b)
m
c)
cm
d)
cm
e)
m
a)
km
b)
m
c)
m
d)
cm
e)
km
f)
m
g)
cm
1. Western Red Cedar
– 5 900 cm
1. Snowy Owl – 66 cm
2. Great Horned Owl
– 63.5 cm
3. Great Gray Owl
– 55 cm
4. Atlantic Puffin
– 34.5 cm
7.
Teacher to check.
8.
a)
83 km, 2 260 m,
3.3 km
b)
877 km, 47 m,
7.5 km
9.
Answers will vary.
AP Book ME6-14
page 276
1.
m = metre
→ length of a
soccer field
1 000 times
fewer
a)
km = kilometre
→ diameter of the
moon
cm = centimetre
→ length of a ruler
1 000 times
larger
Divide by
1000
6.
mm = millimetre
→ length of bee’s
antenna
cm = centimetre
→ diameter of a
drum
2.14 g =
0.00214 kg
Multiply by
10
2.6 dm
= 26 cm
1.
5.2 g
= 5 200 mg
7.2 = 72 mm
c)
AP Book ME6-13
page 274
8.53 kg
= 8 530 g
3.5 = 35 mm
b)
Divide by 10
3.4 mm
= 0.34 cm
2.
a)
100 km/h
b)
80 km/h
c)
25 km/h
d)
160 km/h
a)
25 km
b)
360 km
c)
210 km
d)
210 km
3.
A sneeze is 49.5 km/h
faster than a hurricane.
4.
In 3 hours, Clare can
cycle 18 km further
than Erin.
5.
a)
80 km/h
b)
120 km/h
6.
7.
Jinny, 1.05 km/h
a)
20 km
b)
10 km/h
AP Book ME6-15
page 277
1.
Teacher to check the
comparisons.
Measurements for each
building are as follows:
2. Lodgepole Pine
– 3 050 cm
a)
47 mm, 329 m
b)
33 mm, 231 m
3. Red Oak – 2 400 cm
c)
28 mm, 196 m
4. White Birch
– 2 000 cm
d)
19 mm, 133 m
e)
16 mm, 112 m
f)
11.5 mm, 80.5 m
g)
8 mm, 56 m
h)
7 mm, 49 m
Answer Key for AP Book 6.2
page 3
Measurement – AP Book 6.2 (continued)
2.
6.5 mm, 45.5 m
Lock 7 and Lock 8
b)
4 073 m
j)
8 mm, 56 m
5 010 m
A – 24 m
About 500 m
Distance on map
= 128 mm
c)
a)
d)
6 002 m
D – 30 cm
Actual distance
= 128 × 200
= 25 600 m = 25.6 km
e)
13 241 m
f)
20 002 m
b)
About 10
3.
42 mm
4.
a)
b)
Since 2 buildings
of the Wall Centre
has 96 floors and
is still shorter than
the First Canadian
Place, the 76
floors in the First
Canadian Place
are greater in
height than two
times the floors in
the Wall Centre.
2.
3.
FCP:
47 mm × 7 m/mm
= 329 m
329 m ÷ 72 floors
= 4.57 m / floor.
4.
5.
5.
1.
Lock 2 and Lock 3
2.
Actual distance
= 20 × 200
= 4 000 m = 4 km
3.
183 min
a)
P = 18 cm
b)
P = 16 cm
c)
191 min
d)
250 m
232 m
c)
Yes; 1 × 7
a)
$7.03
d)
12 × 1; 26 units
b)
$16.04
5.
Answers will vary.
c)
$27.03
6.
14 cm
d)
8.06 m
7.
1:6
e)
9.25 m
f)
3.1 cm
i)
9.025 kg
1.
a)
AP Book ME6-18
page 280
1.
2.
a)
2+4+2+1+1+
2 + 1 + 1 = 14 cm
b)
3+6+3+2+1+
2 + 1 + 2 = 20 cm
2.
4.
Answers will vary.
5.
Answers will vary.
a)
528 cents
714 cents
1.
c)
1 003 cents
10
3
12
4
14
5
16
6
18
c)
26
a)
New P = 12 units
b)
or
Original P = 12 units
New P = 12 units
c)
Original P = 14 units
a)
10 cm
b)
8 cm
c)
14 cm
W
L
a)
24 m
1
2
2
1
d)
408 cents
a)
602 cm
b)
409 cm
b)
28 cm
c)
613 cm
c)
6 km
d)
1 153 cm
d)
30 cm
e)
1 420 cm
2.
2
Original P = 10 units
C: 28 units
Answers will vary.
O
Input × 2 + 6
B: 20 units
3.
I
b)
A: 14 units
b)
301 cm
AP Book ME6-20
page 282
16.8 m
AP Book ME6-19
page 281
9 002 m
10 × 1; 2 × 5
12 × 1; 2 × 6;
3×4
326 min
Line should be placed 9
mm south of Lock 2
a)
a)
b)
e)
Teacher to check line.
f)
4.
f)
9.4 dm
AP Book ME6-17
page 279
Estimations will vary.
124 min
8.007 L
Twice the length of the
Welland Canal
= 2 × 44 km
= 88 km
B – 28 cm
3.
a)
h)
6.
e)
b)
g)
Rounding both lengths
(the Welland Canal to
90 km and the Grand
Canal to 1 800 km),
we see that you would
have to travel up and
down the Welland Canal
20 times (1 800 ÷ 90) to
travel the distance of
the Grand Canal.
Lock 1 and Lock 2
Distance on map
= 20 mm
Time spent stopped
= 8 locks × 0.5 h/lock
= 4 hours
= 8 hours and 24
minutes
NOTE:
Answers may vary, depending
on how students place their
rulers. The following distances
assume that students measure
from (and to) the middle of
each lock.
Actual distance
= 13 × 200
= 2 600 m = 2.6 km
4.
Total time spent
= 4 + 4.4 hrs
= 8.4 hours
AP Book ME6-16
page 278
Distance on map
= 13 mm
At 10 km/h, the boat
would travel 20 km in
two hours and would
not reach Lock 8.
Time spent travelling
= 44 km ÷ 10 km/h
= 4.4 hours
Wall Centre:
19 mm × 7 m/mm
= 133 m
133 m ÷ 48 floors
= 2.77 m / floor
1.
C – 6 km
i)
New P = 12 units
3.
P = 6 units
Answer Key for AP Book 6.2
page 4
Measurement – AP Book 6.2 (continued)
W
L
1
5
2
4
3
3
AP Book ME6-21
page 283
AP Book ME5-23
page 285
C: 11 m × 6 m
2
= 66 m
1.
1.
D: 15 km × 10 km
2
= 150 km
P = 12 units
A:
10.8 cm
a)
4 × 3 = 12
B:
8.8 cm
b)
2×3=6
C:
15.6 cm
c)
3×2=6
D:
15.6 cm
W
L
E:
15.2 cm
1
7
F:
19.2 cm
2
6
3
4
2.
a)
W
C
5
2 cm
6 cm
4
3 cm
9 cm
4 cm
12 cm
P = 16 units
W
L
1
8
2
7
3
6
4
b)
a)
5
1.
Yes
8 cm
b)
8 cm
3 × 7 = 21
A – 21 m
b)
3 × 4 = 12
B – 20 cm
c)
3×2=6
d)
4 × 6 = 24
a)
b)
1
8
a)
8 cm
2
10
b)
3 cm
3
12
c)
4 cm
4
14
5
16
6
18
I
O
1
8
2
12
3
16
4
20
5
24
28
c)
2.
3.
9 cm
2
4.
5.
6.
5.
3 cm
Length = 3 units
6.
5 cm
Width = 2 units
7.
a) 2 cm , 2 cm , 4 cm ,
2
2
2
3 cm , 6 cm , 5 cm
To find the area, extend
the lines through the
shape.
2
Area of C = 8 cm
2
Answers will vary –
teacher to check.
Answers will vary –
teacher to check.
5.
3 cm × 4 cm rectangle:
2.
OPTION 2
b)
1 cm × 3 cm
2
= 3 cm
c)
2 cm × 4 cm
2
= 8 cm
Box 1:
2 × 5 = 10
Box 2:
3 × 4 = 12
Total Area: 10 + 12 = 22
d)
4 cm × 3 cm
2
= 12 cm
e)
2 cm × 5 cm
2
= 10 cm
Area = Length × Width
8.
3.
Three possible rectangles:
1 × 12, 2 × 6, and 4 × 3.
AP Book ME6-25
page 287
1.
Shape
P
A
A
12 cm
8 cm
B
22 cm
30 cm
2
C
22 cm
18 cm
2
2
a)
2 cm × 5 cm
2
= 10 cm
D
20 cm
21 cm
2
1 cm × 3 cm
2
= 3 cm
E
26 cm
30 cm
2
b)
F
14 cm
10 cm
2
c)
3 cm × 5 cm
2
= 15 cm
G
22 cm
10 cm
2
a)
6m×7m
2
= 42 m
OR
4 cm × 3 cm rectangle:
2
2 cm × 3 cm
2
= 6 cm
Length = 4 units
AP Book ME6-24
page 286
1.
2
4 × 3 = 12
2
Area of B = 4 cm
2
a)
2
Area of A = 6 cm
6 × 2 = 12
Length = 6 units
b) –c) OPTION 1
Box 1:
2×2=4
Box 2:
3 × 6 = 18
Total Area: 4 + 18 = 22
2
2
2
Width = 3 cm
(since you can find the
width by dividing the area
by the length, and
2
18 cm ÷ 6 cm is 3 cm)
3×2=6
4.
2
4.
Width = 3 units
2
O
Multiply INPUT
by 4 and add 4;
Base 10:
44 toothpicks
5.
a)
2
a)
I
6
C – 66 m
Width = 2 units
The circumference
is about 3 times
greater than the
width.
2
5 × 3 = 15
c)
Multiply INPUT
by 2 and add 6;
Base 10:
26 toothpicks
b)
3.
D – 150 km
d)
AP Book ME6-22
page 284
P = 18 units
4.
2.
2
b)
2.
No
3.
D&G
4.
E – 26 cm
b)
3m×7m
2
= 21 m
B, C & G – 22 cm
c)
4 cm × 8 cm
2
= 32 cm
F – 14 cm
a)
A: 3 m × 7 m
2
= 21 m
D – 20 cm
A – 12 cm
B: 4 cm × 5 cm
2
= 20 cm
Answer Key for AP Book 6.2
page 5
Measurement – AP Book 6.2 (continued)
5.
2
b)
2 whole squares
D – 21 cm
2
c)
3 whole squares
C – 18 cm
2
d)
3 whole squares
e)
8 whole squares
f)
8 whole squares
E & B – 30 cm
F& G – 10 cm
A – 8 cm
2
2
6.
No
g)
4 whole squares
7.
Perimeter is the measure
of the length along the
outside edge of a shape.
Area is the measure of the
space contained within the
edges of a shape.
h)
5 whole squares
i)
11 whole squares
j)
13 whole squares
k)
10 whole squares
a)
7.5 square units
b)
6 square units
c)
7.5 square units
a)
More:
shaded = 7
unshaded = 5
and 7 > 5
AP Book ME6-26
page 288
1.
P
A
A
14 cm
10 cm
2
12 cm
2
16 cm
15 cm
2
D
10 cm
6 cm
2
E
18 cm
14 cm
16 cm
b)
9 half squares =
4.5 total squares
c)
14 half squares =
7 total squares
b)
11. a)
4 half squares
10 000 times more;
Multiply by 10 000;
= 10 total squares
1.34 m
2
= 13 400 cm
6 full squares
c)
146 500 cm
= 7 total squares
d)
1 000 cm
e)
3 760 cm
f)
72 000 cm
i)
a)
Area ≈ 5 units
2
Perimeter ≈ 14 units
b)
Area ≈ 12 units
2
c)
Area ≈ 6 units
2
b)
30 cm
2
c)
3 square units
c)
32 berries
d)
5 square units
d)
a)
Triangle: 3 square
units
$10.00 – $5.98 =
$4.02
2
6.
2
a)
6 cm
b)
20 cm
Rectangle: 2 square
units
2
a)
3 × 3. Area = 9
b)
5 × 5. Area = 25
b)
Teacher to check
drawings.
a)
5 × 2 rectangle
b)
4 × 2 rectangle
c)
NOTE:
For estimation questions,
consider the diagonal of the
square unit equals 1.5 cm.
3 whole squares
d)
7.
AP Book ME6-28
page 292
1.
2.
20 square units
b)
48 – 20 Shaded =
28 Unshaded
a)
3.
8 cm
18 cm
4.
a)
6 wholes squares
5.
b)
8.5 whole squares
600 cm
2
4:1
b)
60 : 15
c)
92 : 23
ii)
One side is a fourth
or quarter of the
total perimeter.
a)
30 : 5
b)
60 : 10
c)
36 : 6
d)
48 : 8
Patti is incorrect because
100 cm = 1 m, then 100
cm × 100 cm
2
= 10 000 cm and
2
1m×1m=1m .
4
2
AP Book ME6-30
page 294
8
1
1.
Length
Width
7
2
14
1
Length
Width
6
3
9
2
18
1
Answers will vary.
BONUS:
a)
2
Width
2
5
5; 9
2.
2
2
Length
2
Triangle: 6 square
units
4.
2
2
14 cm
Rectangle: 3 square
units
3.
a)
Triangle: 4 square
units
Rectangle: 4 square
units
AP Book ME6-27
page 289
Perimeter ≈ 11 units
Triangle: 1 square
unit
Triangle:1 square
unit
2.
Perimeter ≈ 16 units
3 square units
P = 10 cm;
2
2 half squares
b)
5.
b)
8 full squares
P = 8 cm;
2
10 000 cm
10 000 times
smaller;
1 square units
P = 14 cm;
2
a)
Area = 3 + 3 = 6
a)
2
1.
Area = 3 + 4 = 7
2 square units
4.
AP Book ME6-29
page 293
a)
10. a)
Equal:
shaded = 4
unshaded = 4
1
b)
c)
12 cm
a)
2; 4
4 square units
14 cm
A = 6 cm
1.
c)
b)
2
2
G
A = 3 cm
5.
7 half squares =
3.5 total squares
1
2
8 cm
c)
a)
1; 4
a)
12 cm
b)
b)
Less:
shaded = 3
unshaded = 4
and 3 < 4
F
a)
9.
8.5 whole squares
c)
A = 10 cm
4.
b)
R
C
3.
3.
This table gives
the shapes’ actual
measurements only:
B
2.
2.
8.
1
c)
a)
Yes. The part of the
shape that was
taken away from
the first
parallelogram, is
the exact same that
was added to the
second
parallelogram.
b)
Both have a
base of 4
c)
Both have a
height of 5
d)
Area = B × H
a)
4 × 3 = 12 cm
2
Answer Key for AP Book 6.2
page 6
Measurement – AP Book 6.2 (continued)
3.
2
b)
7 × 2 = 14 cm
a)
2
35 cm
b)
12 cm
D:
st
Area of 1 triangle
= (2 × 4) ÷ 2
2
= 4 cm
2
2
c)
48 cm
d)
22.2 cm
a)
A
Area of 2 triangle
= (1 × 4) ÷ 2
2
= 2 cm
2
Teacher to check
that lines are drawn
correctly.
Base
Height
4
4
B
2
5
C
4
5
D
3
4
b)
a)
nd
AP Book ME6-31
page 295
1.
7.
A:
st
Area of 1 triangle
= (2 × 4) ÷ 2
2
= 4 cm
2.
Area of Triangle A = Area
of Parallelogram B ÷ 2
3.
Teacher to check
drawing.
4.
A = (Base × Height) ÷ 2
5.
Area of Triangle A
= (4 × 4) ÷ 2
= 16 ÷ 2
2
= 8 cm
nd
Area of 2 triangle
= (1 × 5) ÷ 2
2
= 2.5 cm
Total Area of B
2
2
= 2.5 cm + 2.5 cm
2
= 5 cm
C:
st
Area of 1 triangle
= (3 × 5) ÷ 2
2
= 7.5 cm
AP Book ME6-32
page 296
1.
2.
3.
4.
nd
Area of 2 triangle
= (1 × 5) ÷ 2
2
= 2.5 cm
Total Area of C
2
2
= 7.5 cm + 2.5 cm
2
= 10 cm
8.
Each shape should
have a height of
two square units
(double the height).
1.
2
a)
6 cm
b)
6 cm
1
4
B
2
8
C
.5
2
D
1
4
12 cm
d)
12.8 cm
2 cm; 16 cm
6 cm
2 times
12.
Teacher to check.
13.
A - 150 cm
2
B - 200 cm
a)
35 cm
b)
170 cm
d)
22 cm
16.
1
2 The triangle has the
same base and height as
the parallelogram.
Therefore the area is half
because when
calculating the area of a
triangle you divide by 2
(A = B × H ÷ 2)
2
6 cm
b)
4 cm
17.
2
18.
2
c)
6 cm
A
9 units
2
B
18 units
2
C
24 units
2
20 units
2
5.
Area = 44 units
6.
a)
2
P = 24 units
A = 28 units
b)
6.5 km; 5.5 km
2
a)
D
15.
2
31.5 cm
2
Less (P = 10 cm)
2
c)
2
14.
2
2
19.
P = 34 units
A = 57 units
2
20.
12
b)
12 cm
c)
1 × 3 × 4 = 12 cm
d)
2 × 3 × 4 = 24 cm
e)
3 × 3 × 4 = 36 cm
3
3
3
3
3
f)
36 cm
g)
36 mL
a)
i)
b)
c)
3.
11.
2
a)
5 cm; 20 cm
10.
2
2.
The area is
quadrupled
(mutliplied by 4).
9.
2
c)
Area
New
Shape
Area
A
C - 225 cm
B:
st
Area of 1 triangle
= (1 × 5) ÷ 2
2
= 2.5 cm
nd
c)
Area of parallelogram
2
= 4 × 4 = 16 units
The area of the triangle is
2
8 cm (half of 16, or 8
2)
units .
AP Book ME6-33
page 299
Shape
Total Area of D
2
2
= 4 cm + 2 cm
2
= 6 cm
Area of 2 triangle
= (2 × 4) ÷ 2
2
= 4 cm
Total Area of A
2
2
= 4 cm + 4 cm
2
= 8 cm
b)
Teacher to check
drawings.
1×3×2
ii)
1×3×3
iii)
1×2×5
i)
5×3×2
ii)
5×3×3
iii)
5×2×5
V=L×W×H
Answers will vary.
Teacher to check.
AP Book ME6-34
page 300
1.
2.
a)
2 700
b)
48 000
c)
6 000
d)
3 400
e)
8 100
f)
1 200
g)
9 800
h)
4 050
i)
2 300
a)
5 000 kg
b)
18 000 kg
c)
6 000 kg
explanation
d)
50 000 kg
16 m. The shaded
triangle is half of the
square, therefore the
area of the square is 16
2.
m Becuase the shape is
a square, we know all
sides must be even (16 =
4 × 4). When all 4 sides
are added, the result is
16cm.
e)
1 500 kg
f)
310 kg
g)
45 500 kg
1
2 , see Q.16 for
4 cm. You can check you
answer by inserting the
numbers into the formula
( A = B × H ÷ 2).
3.
h)
26 000 kg
a)
40, 80, 120, 160,
200, 240, 280, 320,
360, 400, 440, 480,
520, 560, 600, 640,
680, 720, 760, 800,
840, 880, 920, 960,
1000
b)
25
Teacher to check.
Answer Key for AP Book 6.2
Measurement – AP Book 6.2 (continued)
c)
page 7
Answers will vary –
roughly 20 (1 000
kg = 50 kg × 20)
4.
No, the total mass is
about 1 250 kg or 1.25
tonnes and exceeds the
1 tonne limit.
5.
5 000 kg = 5 tonnes
More. An elephant would
eat about 1 050 kg in one
week.
6.
Yes, Merlinda family’s
furniture weighs 1 000
kg, and is less than the
maximum weight of
the truck.
Answer Key for AP Book 6.2