Std : V th Subject : Mathematics.
Sl
No
1)
2)
3)
4)
5)
6)
7)
.
Title
Multiplication.
Division.
Mental Arithmetic.
Money.
Preparation of bill.
Weight and volume.
Time.
1
Multiplication
3256
 6
19536
Find the product:
1. 3759
2. 365
0=0
 1 = 365
Fill the blanks:
1. Any number multiplied by zero the product is zero.
2. Any number multiplied by one the product is the number itself.
Multiply:
1. 3275
3
9825
2. 4764
 25
23820
9528+
119100
6. 248
 212
496
248+
496++
52576
7. 178
142
356
712+
178++
25276
3. 1698
4
6792
4. 3729
 32
7458
11187+
119328
5. 183
208
1464
000+
366++
38064
8. 100
243
300
400+
200++
24300
Solve:
1. Mr. Siddappa is a fruit selling agent who export oranges. One box contains 144
oranges. If he export 259 boxes of oranges, Find the total number of oranges?
Sol: One box
- 144
No. of boxes - 259
144
259
1296
720+
288++
37296
Total oranges – 37,296
2. A dealer buys 27 bicycles for his show room. Cost of each bicycle is Rs.2067. Find
the amount paid by the dealer?
Sol: Cost of bicycle
- 2067Rs.
No. of bicycle
- 27
2
2067
 27
14469
4134+
55809
Total cost – 55809Rs.
3. A lorry covers 13km using 1ltr of diesel. What distance will it cover, if 1,043 litres of
diesel is used?
Sol: Diesel – 1043
Distance per litre – 13
1043
 13
3129
1043+
13559
Total distance cover – 13559km.
4. A factory produces 1575 toys in a day. How many toys will be produce in a year?
(1year = 365days)
Sol: Toys produced in a day – 1575
No. of days – 365
1575
 365
7875
9450+
4725++
574875
Total no. of toys will produce in a year – 5,74,875
5. How many Minutes are there in month of March?
Sol: 1hr = 60min
1day = 24hrs
24hrs = 2460= 1440mins
31day=1440
31
1440
4320+
44640
In the month of march – 44,640min.
6. If the cost of a TV set is Rs. 12500. Find the cost of 48 such sets?
Sol: Cost of a TV set – Rs. 12500
No. of set – 48
12500
 48
100000
50000+
600000
3
Cost of 48 TV sets – Rs. 6,00,000
7. In a protected forest area 160 trees are planted in each row & 108 trees in each
column. Find the total number of trees planted in the forest area?
Sol: Trees planted in each row – 160
No. of trees planted - 108
160
 108
1280
000+
160++
17280
Total trees in each column – 17280
Division
I Find the quotient:
1. 45 ÷ 9
9)45(5
- 45
00
Quotient=5
2. 36 ÷ 3
3)36(12
- 36
00
Quotient=12
3. 72 ÷ 4
4)72(18
-4
32
-32
00
Quotient=18
Find Quotient and Reminder:
1. 474 ÷ 6
6)474(79
-42
054
-054
000
Quotient = 79
Reminder = 00
2. 527 ÷ 12
12)527(43
-48
047
-036
11
Quotient = 43
Reminder = 11
Verification:
Dividend
–DQ+R
527
– 12  43 + 11
527
– 516 + 11
527
– 527
3. 1653 ÷ 8
8)1653(206
-16
0053
- 48
Verification:
Divided
-DQ+R
1653
- 8  206 +5
1653
- 1648 + 5
4
Quotient - 206
Reminder - 05
05
4. 1435 ÷ 15
15)1435(95
-135
0085
- 75
10
1653
- 1653
Verification:
Divided
1435
1435
1435
-DQ+R
-15 95 + 10
- 1425 + 10
-1435
Quotient - 203
Reminder - 10
Find the Quotient and Reminder:
1. 2647 ÷ 13
13)2647(203
-26
0047
Quotient – 203
- 39
Reminder – 8
08
3.
49652 ÷ 22
22)49652(2256
-44
056
- 44
125
-110
0152
- 132
020
2. 12056 ÷ 12
12)12056(1004
-12
00056
- 48
008
Quotient - 1004
Reminder - 08
Quotient - 2256
Remember - 20
Solve the following:
1. A tailor has 18 meters of cloth. He can stitch 9 shirts from this cloth. Find the length
of cloth required to stitch 1 shirt.
Sol: Cloth – 18m
No. of shirt stitched – 9
Cloth needed for 1 shirt – 18 ÷ 9
9)18(2
−18
00
Cloth needed for 1 shirt – 2m.
2. A like can cover 240km with 5litres of petrol. Find how many kilometers does it
cover with 1 liter of petrol.
Sol: Distance covered
– 240km
Petrol
– 5ltr
One litre
- 240÷5
5)240(48
-20
040
- 40
00
One litre – 48km.
5
3. 25004 bags of cement are loaded equally into 14 railway wagons. Find the number of
bags in each wagon.
Sol: No of cement bags - 25004
No of wagon - 14
Cement bags in each wagon – 25004 ÷ 14
14)25004(1786
-14
110
- 98
0120
- 112
0084
- 84
00
Cement bags in each wagon is – 1786.
4. Mr. Sridhar purchased 11toys of same price for Rs. 946 from a toy shop. Cost of each
toy?
Sol: Mr. Sridhar purchased toys – 11
Price of 11 toys – 946
Price of each toy – 946 ÷ 11
11)946(86
- 88
066
- 66
00
Total price of each toy is – 86
5. The annual income of a person is Rs. 90912. Find his monthly income.
Sol: Annual income – 90912.
Months in a year – 12
Monthly income – 90912 ÷ 12
12)90912(7576
-84
069
- 60
091
84
072
72
00
Annual monthly income Rs. 7576.
6
Multiplication and Division sums:
1. An orange garden has 82 orange plants. A former plucks 60 oranges from each plant
and packs 12 oranges in each box. Calculate the number of boxes required to pack all
oranges?
Sol: Orange plants – 82
Oranges in 1 tree – 60
82
 60
00
492+
4920 Total oranges
Oranges in one box – 12
No. of box need – 4920 ÷ 12
12)4920(410
-48
012
- 12
000
0
0
No. of boxes needed = 410.
2. 15 School children hire a cob for a days excursion at 9Rs per km. If they travel a
distance of 325km. Find the amount to be shared by each one of them?
Sol: Total distance – 325
Per km – 9Rs.
325
9
2925 Total amount.
No. of children
– 15
Each should pay
– 2925 ÷ 15
15)2925(195
-15
142
- 135
0075
- 75
00
Each should pay – 195.
7
3. Anita has a cow which yields 8 litres of milk in a day. The selling price of 1ltr of milk
is 18Rs. She wants to divide the amount earned in one month (30days) among her 4
sons . What amount does each one get?
Sol: Sells in 1 day – 8ltrs
One litre cost – Rs. 18.
18
8
144
Amount gets in one month - 144
 30
000
432+
4320
She wants to divide – 4
4320 ÷ 4
4)4320(1080
-4
03
-0
32
- 32
000
Amount each get Rs.1080
4. 25 villages donates 150 each to a higher primary school for scholarship to the needly
students. If there are 30 needly students, Find the scholarship amount received by
each student?
Sol: Villages – 25
Donates – 150Rs.
00
125+
25++
3750 Total amount.
Needy Students – 30
3750 ÷ 30
30)3750(125
- 30
075
- 60
150
- 150
000
Amount received by each students – 125.
8
Mental Arithmetic
Estimation and Approximation
I Round of each off the following numbers to nearest thousands place:
Number
Nearest to 1000places
a)
b)
c)
d)
e)
26674
3469
15238
32658
69794
-
8000
3000
15000
33000
70000.
II Round off each of the following numbers to nearest ten thousands place.
Number
Nearest to 10000places
a)
b)
c)
d)
e)
26674
32464
46379
53668
86976
-
30000
30000
50000
50000
90000.
III Estimate sum of the following by rounding off to nearest thousand
place:
1. 42125
+ 35637
77762
77762
78000
2.
54837
+ 41354
96191
96191
96000
3.
33231
+ 20097
53328
53328
53000
4.
47463
+ 41541
89004
89004
89000
IV Estimate the difference of the following by rounding off to nearest
thousand place:
1. 45630
- 32148
13482
13482
13000
2. 60046
- 15247
44799
44799
45000
V Estimate the difference of the following by rounding off to the nearest
ten thousand place.
1. 57964
- 26875
31089
31089
30000
2. 51689
- 15247
36442
36442
40000.
9
VI Estimate the product of each of the following by rounding off to its
highest place.
1. 428  54
428
 54
1712
2240+
24112
- Its nearest to thousand
- Its nearest tens
400
 50
000
2000+
20000
2. 2645  18
2645 - Its nearest thousand
18 - Its nearest tens
21160
2645+
47610
3000
 20
0000
6000+
60000
3. 5476  11
5476 - Its nearest thousand
11 - Its nearest tens
5476
5476+
60236
5000
10
0000
5000+
50000
VII Estimate the quotient of each of the following by rounding of its highest
place.
1. 3265 ÷ 58
3265 – nearest to 1000
58 – nearest to 10
60)3000(50
- 300
0000
3000
60
Quotient – 50
2. 34657 ÷ 135
34657 – Nearest to 10000
30000
135 – Nearest to 100
100
100)30000(300
- 300
00000
Quotient – 300
10
3. 87416 ÷ 28
87416 - Nearest to 10000
90000
28 - Nearest to 10
30
30)90000(3000
- 90
000
- 0
00
- 0
00
- 0
0
Quotient – 3000
Sovle the following:
1. A train can cover 225km in one hour. Estimate the distance covered in a day to the
hightest place.
Sol: 1hour – 225 km
1day – 24 hour
225  24
225
 24
900
450+
5400
The distance covered in a day = 5400
5000km.
2. A garment company stitched 16783 shirts and 12438 of dresses stitched to the nearest
ten thousand place?
Sol: Shirt – 16783
Pant – 12438
Total – 29221
Total dress stitched = 29221
30000
3. A sweet stall has 1620 laddus. Sweet seller wants to pack 15 laddus in each box.
Estimate the number of boxes required?
Sol: Laddus – 1620
One box – 15
No. of boxes – 1620 ÷ 15
15)1620(108
-15
0120
- 120
000
No. of boxes = 108
100
11
4. A carpenter earned Rs. 18634 during the month of November and Rs. 32645 in
December. Estimate how much more he earned in December to the nearest ten
thousands place.
Sol: November – Rs. 18634
December – Rs. 32645
32645
- 18634
14011
14011 – Nearest to 10000
10000
Rs. 10000 they earn more.
Decimal Fraction
Write in words:
1.
2.
3.
4.
5.
0.5
0.15
1.7
5.21
0.13
– Zero point five.
– Zero point one five.
– One point seven
– Five point two one
– Zero point one three.
Write the numeral representing each of the following.
1.
2.
3.
4.
5.
Zero point one two
Six point eight
Ten point five
Four point zero two
One hundred eight point zero six
– 0.12
– 6.8
– 10.5
– 4.02
– 108.06
Fill in the blanks:
1.
2.
3.
4.
5.
6.
7.
8.
8mm
75mm
8cm 5mm
525mm
8cm
72cm
75paise
870paise
= 0.8cm
= 7.5cm
= 8.5cm
= 5.25cm
= 0.08m
= 0.72m
= 0.75Rs.
= 8.70Rs.
Conversion into decimal:
1.
2.
3.
4.
5.
6/10
83/10
251/100
7/100
1461/100
= 0.6
= 8.3
= 2.51
= 0.07
= 14.61
12
Write the fraction into Decimal
1. 3/4
=
4) 3 (0.75
- 0
30
- 28
020
- 20
00
4. 2/5
=
5) 2 (0.4
-0
20
- 20
00
2/5 = 0.4
3/4 = 0.75
2. 13/20 =
5. 1/2
20) 13 (0.65
- 00
130
- 120
0100
- 100
000
2) 1 (0.5
-0
10
- 10
00
1/2 = 0.5
13/20 = 0.65
3. 38/50 =
=
6. 8/25
50) 38 (0.76
- 00
380
- 350
0300
- 300
000
=
25) 8 (0.32
-0
80
- 75
050
- 50
00
8/25 = 0.32
38/50 = 0.76
Write in fraction:
1. 0.2 =
2
10
2. 0.02 =
2
100
3. 8.03 =
803
100
4. Money.
1)
Find the sum of :
Rs 13.25 + Rs 10.40 + Rs 6.30.
Rs 13.25
Rs + 10.40
Rs + 6.30
29.95
2)
13
Find the difference :
Rs 78.45 –Rs 69.70
Rs 78.45
Rs - 69.70
08.75
2)
Find the product of :
Rs 147.25 X Rs 17.00
Rs 147.25
X Rs17
103075
14725+
2503.25
4)
Find the quotient :
Rs 4960 ÷ Rs 8
8) 4960 (620
- 48
016
- 16
000
00
0
0
Solve:
1)
Soln:
I had Rs 625 with me. My father gave Rs. 450.25 as pocket money with the total amount
with me now?
I had
- Rs. 625
Father Gave
- Rs. 450.75
625.00
+ 450.75
1075.75
2)
Soln:
Total amount Rs. = 1075.75
Sheriff had Rs.15000.75 in his post office account. He further deposited an amount of Rs.
4805.25 to his account in the post office?
Sharif had
- Rs 15000.75
Deposited
- Rs 4805.25
15000.75
+ 4805.25
19806.00
Total amount Rs.= 19806.00.
Solve:
1)
Varun brought sweet for Rs. 475.50. He paid Rs 500 to the Shopkeeper. What change should
be get back from the shopkeeper?
Soln: Paid Rs.
– 500.00
Sweet Rs.
– 475.50
500.00
- 475.50
024.50
Shop keeper gave back = Rs. 24.50.
2)
Soln:
Poornima had Rs. 3425 with her. She gave Rs. 2745.75 to her friend to by a saree. What is
the amount left with her?
Poornima had - Rs. 3425.00
Gave
- Rs. 2745.75
3425.00
- 2745.75
0679.25
Amount left with Poornima = Rs. 679.25.
14
3)
Joseph had Rs. 2500 in his account in a bank. He withdraws Rs. 1800.75 for his expenses.
What is the amount left in his account in the bank?
Soln:
Joseph had in bank – Rs. 2500.00
Withdraw
– Rs. 1800.75
2500
- 1800.75
0699.25
Amount left in account = Rs. 699.25.
Solve:
1)
Soln:
2)
Soln:
3)
Soln:
The cost of an egg is Rs. 4 What is the cost of a dozen eggs?
1 dozen – 12
1 egg – Rs 4
No of eggs – 12
12
X 4
Rs 48
Cost of one dozen Eggs = Rs 48.
The cost of an Umbrella is Rs 225, What is the cost of 15 Umbrellas?
Cost
- 225
No of Umbrella
- 15
225
X 15
1125
225+
3375
Total cost = Rs. 3375.
Laborers earns Rs. 525 a day. How much will be earn in a week?
1 Week
– 7day.
Earn in day – 525 Rs.
No of days
– 7 days.
525
X 7
3675
Earn in a week = 3675 Rs.
Solve:
1)
Soln:
Mohan paid Rs. 1422 for 9 shirts. What is the cost of each shirt?
Shirts – 9
Paid – Rs. 1422
Costof each shirt – Rs?
9) 1422 (158
- 9
52
- 45
072
72
000
Cost of each Shirt = Rs. 158.
15
2)
Soln:
If the cost of dozen apples is Rs. 96. What is the cost of 1 apple?
Apple – 1 dozen -12.
Cost – Rs. 96
Cos of each apple – 96 ÷ 12
12 ) 96 ( 8
- 96
00
Cost of each apple = Rs. 8.
3)
Soln:
Vinod a carpenter earn Rs. 9666 in 6 days. What is the amount he earn in a day?
Earn – Rs. 9666.
No of Days – 6
Earn in each day – Rs? 9666 ÷ 6
6 ) 9666 ( 1611
- 6
36
- 36
006
6
06
6
0
Earn in each day = Rs. 1611.
Solve:
1)
Soln:
2)
Soln:
Subtract Rs. 687.25 from the sum of Rs. 932.60 and Rs. 403.70.
Rs. 932.60
Rs. 1336.30
Rs. 403.70
Rs. 687.25
Rs. 1336.30
Rs. 0649.05
Ramegouda has Rs. 8000 with him. He spent Rs. 2450.25 to buy mango saplings , Rs 675.5
For seedling and Rs. 150 for transportation. What is the amount left with him?
Mango sailing – 2450. 25
Seedling
– 675.50
Transportation – 150.00
Mango sailing – 2450. 25
Ramegouda had – Rs. 8000.00
Seedling
– 675.50
Spent
– Rs. 3275.00
Transportation – 150.00
Rs. 4724.25
3275.75
Amount left with him = Rs. 4724.25.
3)
Soln:
Salma brought 20 chocolates at Rs. 22 each She gave shopkeeper Rs. 500 note, What is the
Change she has to get from the shop keeper?
Each chocolates – Rs. 22
No of chocolates – 20
Rs. 22
X 20
440
Salma has :
Rs. 500
Cost of chocolates : 440
Rs. 500
- 440
060
Shopkeeper gave – Rs. 60
16
5.4
PREPARATION OF BILL.
Preparation bills are the particulars given below. Find the total cost in each case and total cost of all
items.
1)
Satya went to hopcoms shop and brought the following vegetables.
Cali flower – 2 kg at Rs. 18.00 per kg.
Potatoes – 3 kg at Rs. 17.00 per kg.
Beans
– 2 kg at Rs. 19.00 per kg.
Tomatoes – 5 kg at Rs. 19.00 per kg.
Name :- Satya
Sl.no Perticulars
1)
Cauliflower
2)
Potatoes
3)
Beans
4)
Tomatoes
Quaintity
2kg
3kg
2kg
5kg
Total
In words : One hundred and ninety only.
Date: 20/12/12.
Rate Rs.
18.00 Rs. Per kg.
17.00 Rs. Per kg
19.00 Rs. Per kg
13.00 Rs. Per kg
=
Amount Rs.
26
51
38
65
190.00. Rs
Signature .
2)
Mrs. Uma brought the following articles from sunny enterprices.
5 Instrument boxes at Rs. 38 each
12 Pencils at Rs. 3 each.
6 Boxes of crayons at Rs. 12 each.
8 point Boxes at Rs. 25 each
Name: Mrs.Uma
Sl.no Perticulars
1)
Instrument Box
2)
Pencils
3)
Crayons
4)
Point Box
Quaintity
5
12
6
8
Total
In words: Four hundred and ninety eight only.
Date: 02/01/13
Rate Rs.
38
3
12
25
=
Amount Rs.
190.00
36.00
72.00
200.00
498.00
Signature .
17
6. WEIGHT AND VOLUME.
1)
2)
3)
4)
1 Ton = 1000Kg.
1 Quintal = 100kg.
10 Gram = 1 Decagram.
100 Gram = 1 Hectogram.
5)
6)
7)
8)
1000 Grams = 1kg.
500 Grams = ½ kg.
F50 Grams = ¾ kg.
250Grams = ¼ kg.
Ex : 6.1.
Add
1)
4 kg 250Gms,
12kg 355 gms.
2)
4Kg 250 gms
12kg 355 gms
16 kg 605 gms.
2)
12 kg 450 gms, 15 kg 550 gms
12 kg 450 gms
15 kg 550 gms
28 kg 000 gms.
23 kg 432 gms, 37 kg 350 gms
23 kg 432 gms
37 kg 350 gms
60 kg 782 gms.
4)
17 kg 370 gms, 18kg 630 gms
17 kg 370 gms
18 kg 630gms
36 kg 000 gms.
Solve the following.
1)
Soln:
Radha buys 2 kg 500 gms of carrot , 2kg 500 gms of brinjal and 3kg 250gms of tomatoes
From vegetable shop. Find total weight of vegetable bought by her?
Carrot – 2 kg 500 gms
Bringal – 2 kg 500 gms
Tomato – 2 kg 500 gms
8 kg 250 gms.
Total weight bought Radha = 8 kg 250 gms.
2)
A merchant has 68 kg 250gms of wheat with him. He sales 15 kg 250 gms of wheat to one
customer and 13 kg 500 gms to another customer. What is the weight reaming with him?
Soln:
Sold.
1 st customer – 15 kg 250 gms.
Wheat – 68kg 250 gms.
nd
2 customer – 13 kg 500 gms.
Sold
– 28kg 750 gms.
28 kg 750 gms.
39 kg 500 gms.
Total weight of wheat Remained = 39kg 500gms.
3)
Soln:
18 kg 400 gms of sugar is to be packed in 4 bag equally, What is the weight of each bag.
Sugar – 18 kg 400 gm.
No bags – 4nos
Sugar in each bag : 18.400 ÷ 4
4 ) 18.400 ( 4.600
- 16
02 4
24
00 0
0
00
0
0
Sugar in each bag : 4 Kg 600 gms.
18
4)
Soln:
4 merchants to gather purchased 8 bags of rice each bag contained 24 kg 500 gms of rice. If
They divide the rice equally among themselves what is the weight of rice each one gets?
Rice in each bag – 24.500 kg
X 8
196.000 kg
Total Rice = 196.000kg.
No merchants – 4Nos.
4) 196 ( 49
- 16
036
- 36
00
Each one get = 49 kgs.
VOLUME
Add
1)
Subtract
3 ltr 250 ml
+ 6 ltr 500 ml
+
750 ml
10 ltr 500 ml.
2)
15 ltr 450 ml
+ 5 ltr 350 ml
+ 21 ltr 750 ml
42 ltr 550 ml.
1) 25 ltr 350 ml
- 15 ltr 750 ml
09 ltr 600 ml
2) 64 ltr 450ml
- 24 ltr 550 ml
39 ltr 900 ml
Fill in the blanks.
1)
2)
3)
The unit of volume is liter.
1 liter = 1000 ml.
1000 liter = 1 kiloliter.
4)
5)
6)
6kiloliter = 6000 liter.
500 ml = ½ liter.
8000 liter = 8 kilo liter.
Solve :
1)
Soln:
2)
Soln:
A bottle contains 16 ltr 500 ml of sandal oil. It has filled into bottles of 250 ml each. How
Many bottles are required?
Sandal oil
– 1 ltr 500 ml.
Each bottles – 250 ml.
Required
–?
1500 ÷ 250
250 ) 1500 ( 6
- 1500
0000
Bottles Required = 6 Nos.
A can contains 16 ltr 500 of petrol. Find the total quantity of petrol contained in 25 such
Tins?
Each can contains – 16 ltr 500 ml.
No of can
X
25
82500
33000+
412500
Total quantity of Petrol = 412 ltr 500 ml.
19
3)
Soln:
4)
Soln:
5)
Soln:
6)
Soln:
Raju has 14 can of milk. Each one of them contains 8 ltr 500 ml of milk. He fall all the milk
Into four big cans of the same size. What is the quantity of milk contained in big can?
Milk in each can – 8.500 ltr.
No of cans
– X 14
119.000
Total milk
– 119
4 ) 119 ( 29.75
No of cans –
4
8
39
36
030
28
20
20
00
Milk contained in each big can = 29 lit 75 ml.
From a vessel of 500 ml capacity, a pot was filled by pouring water 20 times into it. What is
The total quantity of water in the pot?
Capacity of a pot
– 500
No of pouring water –X 20
000
1000+
10000
Total quantity of water = 10000 lt.
Veena buy 3 ltr 250ml of ground nut oil while returning from her officer. Now her mother
Also bought 1 lit 500 ml of ground nut oil on the someday. What is the total quantity of
Ground nut bought by them?
Veena by ground oil
–
3 ltr 250 ml.
No of oil the same day – + 1ltr 500 ml.
4 ltr 750 ml.
Total quantity of ground nut oil = 4ltr 750ml.
A milk man has 25 liters of milk. he sells 16 liter 750 ml of it. Find the quantity of milk left
With him?
Milkman has milk – 25 ltr
He sells
– 16ltr 750 ml.
25 ltr 000 ml.
- 16 ltr 750 ml.
08 ltr 250 ml.
Total quantity of milk left with him = 8ltr 250 ml.
20
7. TIME.
Ex. 7.1
60 sec – 1 min.
60 min – 1 hour.
24 hr – 1 day.
I)
Donate the following timings in a.m. and p.m.
1)
2)
3)
10.15 morning. – 10.15 a.m.
8.10 night.
– 8.10 p.m.
1.45 afternoon – 1.45 p.m.
4)
5)
6)
4.30 morning
9.45 night
5.35 evening
– 4.30 a.m.
– 9.45 p.m.
– 5.35 p.m.
II) Convert the following timings to 12 hour clock. Timing. Also write in
am and pm.
1)
4)
23.25 hour
2)
23.25
-12.00
11.25 a.m. = 11.25 p.m.
11.55 hour
11.25 = 11.25 a.m.
18.40 hour
18.40
- 12.00
06.40 = 6.40 p.m.
5) 16.45 hour
16.45
- 12.00
04.45 = 4.45 p.m.
Ex – 7.2
1)
3 hr 15 min 18 sec and 1 hr 19 min 17 sec.
Hour : min : Sec
3
: 15 : 18
1
: 19 : 17
4
: 34 : 35
4 hr 34 min 35 sec.
2)
2 hr 30 min 40 sec and 4 hr 50 min 30 sec.
Hour : Min : Sec
1 min = 60 sec.
2
: 30 : 40
60 sec = 1 min.
4
: 50 : 30
60 min = 1 hour.
6
: 80 : 70
6 80 70
± 60 60
7 21 10
3)
7 Hr 21 min 10 sec.
3 yr +8 mth and 2yr 7mth
3 yr 8 mth
2yr 7 mth
5 yr 15 mth
5+1 - 12 mth
6 year 03 mth
6 year 3 mth.
21
3) 8.30 hour
8.30 = 8.30
4)
5yr 6 mth and 4 yr 9 mth
Yrs
mth
5
6
+ 4
9
9
15
- 12
9yr+1 03
10 Year 3 mth.
Ex 7.3
1)
Subtract the following.
3 hr 20 min 25 sec from 4hr 40 min 50 sec.
Hr
4
- 3
1 :
2)
Min
7
32
55 :
min
80
30
50 :
Sec
90
40
50
4 year 11 month from 7 year 5 month.
Yr
6
4
2
4)
Sec
97
45
52
6 hr 30 min 40 sec from 9 hr 21 min 30 sec.
Hr
8
6
2 :
4)
Sec
50
25
25
1 hr 32 min 45 sec from 3 hr 28 min 37 sec.
Hr
2
1
1 :
3)
Min
40
20
20 :
mth
: 17
: 11
: 06
2 years 6 months.
3 year 8 months from 6 year 4 mth.
5 yr 16 mth
3 yr 8 mth
2 yr 8 mth
22
Ex. 7.4
Solve :
1)
Soln:
2)
Soln:
3)
Soln:
A student enters the examination hall at10:30 am. He completes his examination and
leaves the examination hall at 1.00 pm. How many hours did he has spend in the
examination hall?
Enter the hall – 10: 30 am.
Leave the hall – 1:00 pm.
11. 60
12. 00
10. 30
01: 30
1: 00
2: 30
He spends 2 hour 30 min in the examination hall.
The student of a school leaves at 8:30 am on one day school picnic. They finished
their picnic and returned to school at 8:00 pm. How many hours did they spend in the
picnic including journey time?
Left
–
8:30 am.
Leaves –
8:00 pm.
11: 60
12: 00
8: 30
3: 30
+ 8: 00
11: 30
Hours spend in the picnic or journey=11 hr 30 min.
Shayam comes to his office at 9: 00 am. He works 8 hour in office. What time does he
leave his office in the evening?
Comes to office – 9: 00 am.
Works
– 8 hours.
17
- 12
05
He leaves his office at = 5 pm.
4)
A worker enters the factory at 6:15 am. He finishes his work and leaves the factory at
2: 15 Pm. For how many hours he worked in factory?
n
Sol : Enters – 6:15
Leaves – 2:15
11 : 60
12 : 00
- 6 : 15
5: 45
+ 2: 15
7 : 60 = 8 hours.
He worked in factory = 8 Hours.
23