E2 solution 1 (a) Brief explanation with reference to appropriate resonance structures C C Even though OEt is an electron donating group, and –CN is an electron withdrawing group, there are significant resonance contributors that impart single bond character to the C=C N N O O 1 (b) Brief explanation with reference to appropriate resonance structures O O OCH3 OCH3 2(a) 3-ethyl-3-hexene c 2(b) isopropyloxybenzene, C6H5-OCH(CH3)2 g 2(c) 4’-methylacetophenone, para CH3-C6H4-COCH3 h 3. compound A 1-octene In the p-isomer, electron density from the OMe group is delocalized through to the C=O. In the m-isomer, although there are a number of reasonable resonance contributors, the electron density cannot be delocalized through to the C=O. trans-2-octene b a 4-isopropylphenol, para (CH3)2CH-C6H4-OH d 2-(1-propyl)phenol, ortho CH3(CH)2-C6H4-OH f 4-(1-propyl)phenol, para CH3(CH)2-C6H4-OH e 4-methoxystyrene, para CH3O-C6H4-CH=CH2 k 3. compound B propiophenone, 2-phenylpropanal, PhCOCH2CH3 C6H5CH(CH3)CHO j i 3. compound C O Ph COOH O SODAR = 5, IR⇒ o-disubstituted benzene, no C=C oop SODAR = 2, IR⇒non-congugated COOH, no C=C SODAR = 5; IR⇒benzene ring, monosubstituted; high C=O freq ⇒phenyl on O of ester. 4. compound D 4. compound E 5. compound F See below 5. compound F It is difficult to reconcile all the data…so, credit for the following clues: 1. IR ⇒ C≡C? (or C≡N?) 2. IR ⇒ conjugated C=O (i.e., rel. low freq.); 3. IR ⇒ Monosubstituted phenyl ring 4. MS ⇒ M+ suggests even number of N (or zero) 5. M+1 suggests C9 6. NMR⇒benzene ring, and one other type of proton (CH3?), but what is the integral ratio? 6:4? 7. 5:3 would be better since you know that there is a monosubstituted benzene ring. In which case, the 3H signal is likely to be a CH3. Now, if you insist on a real structure…. C6H5, C≡N, C=O and CH3 adds up to mass of 146, but C9H8NO cannot be a molecular formula! What about C6H5, C≡C, C=O and CH3? C10H8O (M = 144)? Possibly an error in measuring height of tiny (2.2%) M+1 peak in MS? …, so…? … you got lots of credit for clues
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