Biol 1408 : Chapter 9 Patterns of Inheritance The Experiment P generation (true-breeding parents) We previously discussed mono hybrid crosses × Purple flowers F1 generation White flowers All plants have purple flowers Fertilization among F1 plants (F1 × F1) F2 generation 3 of plants 1 of plants 4 4 have purple flowers have white flowers Mono Hybrid Crosses A cross between true breeding plants that differ in only one character trait Examples such as flower color, plant height, pod color, pod shape,… Outcome of F2 generation was 3:1 with respect to phenotype With respect to genotype , the outcome is 1:2:1 1 9.5 Dihybrid Crosses A dihybrid cross is a mating of parental varieties that differ in two characters. Mendel performed the following dihybrid cross Parent 1 : Round seeds ( 1st character state) that were yellow colored (2nd character state) Parent 2 : Wrinkled seeds ( variation on 1st character state) that were green colored (variation on 2nd character state) (from earlier discussion, round and yellow are dominant traits) © 2012 Pearson Education, Inc. 9.5 Dihybrid Crosses First, how do we represent an organism with two character state ? A one character state with respect to color (yellow) is represented as YY (homozygous dominant), Yy (heterozygous), or yy (homozygous recessive). Two character states, such as Round and Yellow seeds, can thus be represented as RR YY ( homozygous dominant for both traits) Rr Yy (heterozygous for both traits) rr yy (homozygous recessive for both traits) © 2012 Pearson Education, Inc. 9.5 Dihybrid Crosses Mendel reasoned that if seed shape and seed color were traits related to each other, they should sort out evenly in the gametes. rryy P generation RRYY Gametes RY × ry Since the parents are double homozygous, the gametes don t immediately tell the story of what happens. What will a cross between these two plant above give us ? © 2012 Pearson Education, Inc. 2 9.5 Dihybrid Crosses rryy P generation RRYY Gametes RY × ry RrYy F1 generation The F1 generation is thus 100 % double heterozygous. And since R ( round) and Y (yellow) are dominant characteristics, all seeds from the F1 generation plants will yield round, yellow seeds. 9.5 Dihybrid Crosses rryy P generation RRYY Gametes RY × ry RrYy F1 generation What if we now do a cross between F1 plants ? Since Mendel thought that parental traits are always related to each other, so they should sort out in the gametes together. 9.5 Dihybrid Crosses rryy P generation RRYY Gametes RY F1 generation × ry RrYy In other words, if the traits were dependent on each other, they should sort out dependently into the gametes ( called dependent assortment) Thus the R and Y trait, coming from the one parents would always travel together, and the r and y trait would do the same as well 3 9.5 Dihybrid F1 cross assuming parental traits are related The gametes would contain the parental traits if they are related by parental origin (dependent assortment) The expected outcomes would thus be 3:1 in phenotypes (3 showing round and yellow seeds, 1 having wrinkled green seeds) RY ry RY RRYY RrYy ry RrYy rryy gametes Female Male RrYy RrYy 9.5 Dihybrid F1 cross assuming parental traits are related F1 generation RrYy Sperm 1 2 1 2 F2 generation RY 1 2 ry RY Eggs 1 2 ry Data did not support this hypothesis of dependent assortment of parental traits and resulted in rejection of this hypothesis. 9.5 The law of independent assortment is revealed by tracking two characters at once Mendel observed the following when performed this dihybrid cross : – P generation: round yellow seeds × wrinkled green seeds – F1 generation: all plants with round yellow seeds – F2 generation: – 9/16 had round yellow seeds – 3/16 had wrinkled yellow seeds – 3/16 had round green seeds – 1/16 had wrinkled green seeds Two new phenotypes not observed in either P or F1 generation © 2012 Pearson Education, Inc. 4 9.5 Dihybrid Crosses rryy P generation RRYY Gametes RY ry × RrYy F1 generation The only way this could have happened if the traits sorted out independently of each other in the gametes Instead of two possibilities in the gametes, 4 possibilities can occur. 9.5 Dihybrid Crosses rryy P generation RRYY Gametes RY ry × F1 generation RrYy RY Possible gametes Ry rY ry • The traits thus move independent of each other into the gametes, generating 4 possible gamete formation • Called independent assortment of the traits • A punnett square will show all the possible combinations. 9.5 Dihybrid Cross among F1 plants with independent sorting out of traits in gametes RrYy F1 generation Sperm 1 4 1 4 RY 1 4 rY Eggs 1 4 Ry 1 4 ry RY 1 4 rY 1 4 Ry 1 4 ry RRYY RrYY RRYy RrYy RrYY rrYY RrYy rrYy RRYy RrYy RrYy rrYy RRyy Rryy Rryy rryy 9 16 Yellow round 3 16 Green round 3 16 Yellow wrinkled 1 16 Green wrinkled 5 9.5 The law of independent assortment is revealed by tracking two characters at once Mendel observed that the F2 offspring – a 9:3:3:1 phenotypic ratio. – had new non-parental combinations of traits – 9 showing double dominant trait, 3 heterozygous in 1st trait and homozygous in 2nd trait, 3 homozygous in 1st trait and heterozygous in 2nd trait, 1 double recessive Mendel – suggested that the inheritance of one character has no effect on the inheritance of another, – suggested that the dihybrid cross is the equivalent to two independent monohybrid crosses ((3:1) x (3:1)) – He called this the law of independent assortment. © 2012 Pearson Education, Inc. 9.5 Dihybrid Cross among F1 plants with independent sorting out of traits in gametes Sperm 1 of RR YY 2 of RR Yy 2 of Rr YY 4 of Rr Yy 9 1 of RR yy 2 of Rr yy 3 1 of rr YY 2 of rr Yy 1 of rr yy RrYy F1 generation Genotypes 3 1 1 4 1 4 RY 1 4 rY Eggs 1 4 1 4 RY 1 4 rY 1 4 Ry 1 4 ry RRYY RrYY RRYy RrYy RrYY rrYY RrYy rrYy RRYy RrYy RRyy Rryy RrYy rrYy Rryy rryy Ry ry 9 16 Yellow round 3 16 Green round 3 16 Yellow wrinkled 1 16 Green wrinkled 9.5 The law of independent assortment is revealed by tracking two characters at once The following figure demonstrates the law of independent assortment as it applies to two characters in Labrador retrievers: – black versus chocolate color, – normal vision versus progressive retinal atrophy (blindness). – Black and normal vision are dominant traits © 2012 Pearson Education, Inc. 6 What is the result Blind if we cross these two animals ? Phenotype Black coat, normal vision BBNN Genotype Black coat, blind (PRA) B_nn Blind Chocolate coat, Phenotype blind (PRA) bbnn Genotype Chocolate coat, normal vision bbN_ F1 100 % Double heterozygous Black coat, normal vision BBNN Black coat, normal vision BbNn BBNN gives gametes of BN Blind Chocolate coat, bbnn gives normal vision bbN_ gametes of bn Chocolate coat, blind (PRA) bbnn 9.5 Dihybrid Cross among F1 Labradors with independent sorting out of traits in gametes BbNn F1 generation Genotypes 1 of BB NN 2 of BB Nn 2 of Bb NN 4 of Bb Nn 9 2 of Bb nn 1 of BB nn 3 1 of bb NN 2 of bb Nn 3 1 of bb nn 1 BN Sperm bN Bn bn BN BBNN BBNn BbNN BbNn Bn BBNn BBnn BbNn Bbnn 9 of 16 Black Normal 3 of 16 Black blind 3 of 16 Brown Normal 1 of 16 Brown Blind Eggs bN BbNN bn BbNn Bbnn BbNn bbNN bbNn bbNn bbnn 7 9.5 The law of independent assortment is revealed by tracking two characters at once The result of a cross between two F1 animals Mating of double heterozygotes (black coat, normal vision) BbNn × BbNn Blind Blind Phenotypic ratio of the offspring 9 Black coat, normal vision 3 Black coat, blind (PRA) 1 3 Chocolate coat, Chocolate coat, blind (PRA) normal vision 9.5 The law of independent assortment is revealed by tracking two characters at once Blind Blind Phenotypic ratio of the offspring 9 Black coat, normal vision 3 Black coat, blind (PRA) 1 3 Chocolate coat, Chocolate coat, blind (PRA) normal vision 9 have at least one copy of each dominant trait 3 have at least one copy of the dominant allele of the 1st trait and no dominant allele of the 2nd trait 3 have at least one copy of the dominant allele of the 2nd trait and no dominant allele of the 1st trait 1 has only recessive alleles of both traits 8
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