2017-2-9 fctor a greater than 1.notebook

2017­2­9 fctor a greater than 1.notebook
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2/10
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pg 395 #3-21 odd
HW
Answers
February 10, 2017
2017­2­9 fctor a greater than 1.notebook
Today's Objective:
2
Factoring ax + bx + c when a>1
(use splitting linear term/factor by grouping)
February 10, 2017
2017­2­9 fctor a greater than 1.notebook
February 10, 2017
When you have trinomials that look like this....
3x2 + 2x - 5
a > 1, you will use the method called
"Splitting the linear term" or "Factor
by grouping"
Splitting the linear term method
(also called factor by grouping)
Factoring trinomials in the form ax2 + bx +c when a>1
Completely factor 2x2 + 9x + 4
.
1) Find a c
2) Find the two factor pairs
of ac that add to the center term b. 3) Write the center term using the sum
of the 2 new factors, including the proper signs
4) Group the terms to form pairs ­ the first 2
terms and the last 2 terms. Factor each pair
by finding common factors.
5) Factor out the shared (common) binomial parentheses
2017­2­9 fctor a greater than 1.notebook
6 x2 + 5 x - 6
Ex: 2
-4x2 + 4x - 1
February 10, 2017
2017­2­9 fctor a greater than 1.notebook
February 10, 2017
Ex: 3
6x2 + 7x - 20
Your turn!
3t2 + 8t + 4
4x2 - 9s + 5
-2t2 - 5t - 3
-5x2 + 6s - 1
2017­2­9 fctor a greater than 1.notebook
February 10, 2017
2017­2­9 fctor a greater than 1.notebook
February 10, 2017